[Metamath] Re: How tricky is it to define predicate calculus without equality?

2021-09-17 Thread Norman Megill
You may want to look at the [Tarski] reference at http://us.metamath.org/mpeuni/mmset.html#bib showing how to formulate predicate calculus without equality on p. 78: Tarski, Alfred, "A Simplified Formalization of Predicate Logic with Identity," Archiv für Mathematische Logik und

[Metamath] How tricky is it to define predicate calculus without equality?

2021-09-17 Thread Gustavo Gonçalves
It seems like if one wants to define equality instead of "axiomizing" it, it would be as |- ( x = y <-> A. w ( w e. x <-> w e. y ) ) So I started doing a little digging to how much things would change if we used that instead. ax-7 |- ( x = y -> ( x = z -> y = z ) ) I think we can derive ax-7