Re: [Mingw-w64-public] printf(%*.*f,d) broken?
hmm. I got this example from p.85 of howard w sams co.e3 The Waite Group's C
Primer Plus User-Friendly Guide to the C Programming Language Revised Edition.
ISBN 0-672-22582-4 (MSVC 4.x)
I didn't think it was in error. but books could be in error.
From: K. Frank kfrank2...@gmail.com
To: mingw64 mingw-w64-public@lists.sourceforge.net
Sent: Friday, May 9, 2014 5:00 PM
Subject: Re: [Mingw-w64-public] printf(%*.*f,d) broken?
Hi Jim!
On Fri, May 9, 2014 at 5:29 PM, Jim Michaels j...@yoohoo.com wrote:
I could not find a good example on this because examples in books are scarce
as hen's teeth. search engines ignore the * character and maybe even
interpret it like a wildcard. :-/ so examples on the web
are out.
#include stdio.h
int main(void) {
double d=1234567890.123456789;
int width=7,precision=3;//tried 3 and 9
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
//generates forever loop of spaces, program hangs.
return 0;
}
I think that you have too few arguments to your printf call.
I don't actually know what %*.*f does, but I assume it uses printf
arguments to specify the actual format. But (according to my
assumption) width=%d, precision=%d has already used up the
arguments that %*.*f is expecting.
When I change the line
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
to
printf(width=%d, precision=%d, d=%*.*f\n, width, precision,
width, precision, d);
the program works as I would expect, printing out
width=7, precision=3, d=1234567890.123
I need to use this. but it seems broken. it just locks up generating spaces
no matter what I put in for numbers. I don't think that's right.
Jim Michaels
...
Good luck.
K. Frank
--
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Re: [Mingw-w64-public] printf(%*.*f,d) broken?
http://en.cppreference.com/w/c/io/fprintf#Parameters
according to this and the old C book I have,
printf(%*.*f, width, precision, width, precision, value);
is wrong.
it should be
printf(%*.*f, width, precision, value);
see
http://stackoverflow.com/questions/16413609/printf-variable-number-of-decimals-in-float
From: K. Frank kfrank2...@gmail.com
To: mingw64 mingw-w64-public@lists.sourceforge.net
Sent: Friday, May 9, 2014 5:00 PM
Subject: Re: [Mingw-w64-public] printf(%*.*f,d) broken?
Hi Jim!
On Fri, May 9, 2014 at 5:29 PM, Jim Michaels j...@yoohoo.com wrote:
I could not find a good example on this because examples in books are scarce
as hen's teeth. search engines ignore the * character and maybe even
interpret it like a wildcard. :-/ so examples on the web are out.
#include stdio.h
int main(void) {
double d=1234567890.123456789;
int width=7,precision=3;//tried 3 and 9
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
//generates forever loop of spaces, program hangs.
return 0;
}
I think that you have too few arguments to your printf call.
I don't actually know what %*.*f does, but I assume it uses printf
arguments to specify the actual format. But (according to my
assumption) width=%d, precision=%d has already used up the
arguments that %*.*f is expecting.
When I change the line
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
to
printf(width=%d, precision=%d, d=%*.*f\n, width, precision,
width, precision, d);
the program works as I would expect, printing out
width=7, precision=3, d=1234567890.123
I need to use this. but it seems broken. it just locks up generating spaces
no matter what I put in for numbers. I don't think that's right.
Jim Michaels
...
Good luck.
K. Frank
--
Is your legacy SCM system holding you back? Join Perforce May 7 to find out:
• 3 signs your SCM is hindering your productivity
• Requirements for releasing software faster
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Re: [Mingw-w64-public] printf(%*.*f,d) broken?
this is a copy I pasted from another thread to let you know I got the problem
solved.
I found code that resolves my issue and I get
the formatting I want (which what I really want is a quantity of left-hand-side
digits and a qty of right-hand-side digits).
printf(precision=%d, d=%*.*f\n, width, precision, d); //generates forever
loop of spaces, program hangs.
#include cstdio//stdio.h
int main(void) {
int lhsNumDigits=9, rhsNumDigits=5, width=lhsNumDigits+rhsNumDigits+1,
precision=rhsNumDigits;
//floats
printf(d=%0*.*f\n, width, precision, 55.292);
//d=00055.29200
printf(d=%*.*f\n, width, precision, 55.292);
//d= 55.29200
//strings too.
printf(d=%*s\n, 5, abc);
//d= abc
printf(d=%*s\n, 5, abcdefghi);
//d=abcdefghi
return 0;
}
thanks folks. problem resolved.
From: K. Frank kfrank2...@gmail.com
To: mingw64 mingw-w64-public@lists.sourceforge.net
Sent: Friday, May 9, 2014 5:00 PM
Subject: Re: [Mingw-w64-public] printf(%*.*f,d) broken?
Hi Jim!
On Fri, May 9, 2014 at 5:29 PM, Jim Michaels j...@yoohoo.com wrote:
I could not find a good example on this because examples in books are scarce
as hen's teeth. search engines ignore the * character and maybe even
interpret it like a wildcard. :-/ so examples on the web are out.
#include stdio.h
int main(void) {
double d=1234567890.123456789;
int width=7,precision=3;//tried 3 and 9
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
//generates forever loop of spaces, program hangs.
return 0;
}
I think that you have too few arguments to your printf call.
I don't actually know what %*.*f does, but I assume it uses printf
arguments to specify the actual format. But (according to my
assumption) width=%d, precision=%d has already used up the
arguments that %*.*f is expecting.
When I change the line
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
to
printf(width=%d, precision=%d, d=%*.*f\n, width, precision,
width, precision, d);
the program works as I would expect, printing out
width=7, precision=3, d=1234567890.123
I need to use this. but it seems broken. it just locks up generating spaces
no matter what I put in for numbers. I don't think that's right.
Jim Michaels
...
Good luck.
K. Frank
--
Is your legacy SCM system holding you back? Join Perforce May 7 to find out:
• 3 signs your SCM is hindering your productivity
• Requirements for releasing software faster
• Expert tips and advice for migrating your SCM now
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Re: [Mingw-w64-public] printf(%*.*f,d) broken?
Hi Jim!
On Fri, May 9, 2014 at 5:29 PM, Jim Michaels j...@yoohoo.com wrote:
I could not find a good example on this because examples in books are scarce
as hen's teeth. search engines ignore the * character and maybe even
interpret it like a wildcard. :-/ so examples on the web are out.
#include stdio.h
int main(void) {
double d=1234567890.123456789;
int width=7,precision=3;//tried 3 and 9
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
//generates forever loop of spaces, program hangs.
return 0;
}
I think that you have too few arguments to your printf call.
I don't actually know what %*.*f does, but I assume it uses printf
arguments to specify the actual format. But (according to my
assumption) width=%d, precision=%d has already used up the
arguments that %*.*f is expecting.
When I change the line
printf(width=%d, precision=%d, d=%*.*f\n, width, precision, d);
to
printf(width=%d, precision=%d, d=%*.*f\n, width, precision,
width, precision, d);
the program works as I would expect, printing out
width=7, precision=3, d=1234567890.123
I need to use this. but it seems broken. it just locks up generating spaces
no matter what I put in for numbers. I don't think that's right.
Jim Michaels
...
Good luck.
K. Frank
--
Is your legacy SCM system holding you back? Join Perforce May 7 to find out:
#149; 3 signs your SCM is hindering your productivity
#149; Requirements for releasing software faster
#149; Expert tips and advice for migrating your SCM now
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