matching escape string , doesn't work ?

2010-07-05 Thread Aaron Lewis 
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Hi,
echo %A3 | sed 's/(%[0-9A-Z]{2})//g'

I'd like %A3 like string to be removed , what's wrong with my script ?

Thanks.


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Re: matching escape string , doesn't work ?

2010-07-05 Thread Bret S. Lambert 
On Mon, Jul 05, 2010 at 06:35:01PM +0800, Aaron Lewis wrote:
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 Hi,
   echo %A3 | sed 's/(%[0-9A-Z]{2})//g'
 
   I'd like %A3 like string to be removed , what's wrong with my script ?
 

According to the sed manpage, it doesn't use {} in this way; you seem
to be using the wrong syntax (although sed veterans can likely give a
more thorough answer).

try sed 's/%[0-9A-Z][0-9A-Z]//g'(minus any typos/thinkos on my part)

   Thanks.
 
 
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[SOLVED] Re: matching escape string , doesn't work ?

2010-07-05 Thread Aaron Lewis 
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On 07/05/2010 06:42 PM, Bret S. Lambert wrote:
 sed 's/%[0-9A-Z][0-9A-Z]//g'

Thanks , and same for VIM.

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Re: matching escape string , doesn't work ?

2010-07-05 Thread Otto Moerbeek 
On Mon, Jul 05, 2010 at 06:35:01PM +0800, Aaron Lewis wrote:

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 Hi,
   echo %A3 | sed 's/(%[0-9A-Z]{2})//g'
 
   I'd like %A3 like string to be removed , what's wrong with my script ?

sed uses basic re's by default. Gnu sed implements { } by default as
an extensiomn to Posix, we do not. use -E. 


-Otto

Re: matching escape string , doesn't work ?

2010-07-05 Thread William Boshuck 
On Mon, Jul 05, 2010 at 12:42:51PM +0200, Bret S. Lambert wrote:
 On Mon, Jul 05, 2010 at 06:35:01PM +0800, Aaron Lewis wrote:
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  Hi,
  echo %A3 | sed 's/(%[0-9A-Z]{2})//g'
  
  I'd like %A3 like string to be removed , what's wrong with my script ?
  
 
 According to the sed manpage, it doesn't use {} in this way; you seem
 to be using the wrong syntax (although sed veterans can likely give a
 more thorough answer).
 
 try   sed 's/%[0-9A-Z][0-9A-Z]//g'(minus any typos/thinkos on my part)

sed(1) uses basic regular expressions (see re_format(7) for
details).  In particular, you should prepend with a backslash
the parentheses and braces in the original example, although
the parentheses are superfluous for the stated purpose.  If
you want to use bounds, then

echo %A3 | sed 's/%[0-9A-Z]\{2\}//g' 

will do.

[SOLVED] Re: matching escape string , doesn't work ?

2010-07-05 Thread Aaron Lewis 
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On 07/05/2010 07:18 PM, Otto Moerbeek wrote:
 On Mon, Jul 05, 2010 at 06:35:01PM +0800, Aaron Lewis wrote:
 
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 Hi,
  echo %A3 | sed 's/(%[0-9A-Z]{2})//g'

  I'd like %A3 like string to be removed , what's wrong with my script ?
 
 sed uses basic re's by default. Gnu sed implements { } by default as
 an extensiomn to Posix, we do not. use -E. 
 
 
   -Otto

Understand , i'd notice it.


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[SOLVED] Re: matching escape string , doesn't work ?

2010-07-05 Thread Aaron Lewis 
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On 07/05/2010 07:18 PM, William Boshuck wrote:
 On Mon, Jul 05, 2010 at 12:42:51PM +0200, Bret S. Lambert wrote:
 On Mon, Jul 05, 2010 at 06:35:01PM +0800, Aaron Lewis wrote:
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 Hash: SHA1

 Hi,
 echo %A3 | sed 's/(%[0-9A-Z]{2})//g'

 I'd like %A3 like string to be removed , what's wrong with my script ?


 According to the sed manpage, it doesn't use {} in this way; you seem
 to be using the wrong syntax (although sed veterans can likely give a
 more thorough answer).

 try  sed 's/%[0-9A-Z][0-9A-Z]//g'(minus any typos/thinkos on my part)
 
 sed(1) uses basic regular expressions (see re_format(7) for
 details).  In particular, you should prepend with a backslash
 the parentheses and braces in the original example, although
 the parentheses are superfluous for the stated purpose.  If
 you want to use bounds, then
 
 echo %A3 | sed 's/%[0-9A-Z]\{2\}//g' 
 
 will do.

Yep , should escape it , that's the problem


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