Re: [MORPHMET] Doubts about Error Measurement

2016-03-15 Thread Liu Idárraga
And respect to the total error, the sum of the % SSimage + % SSdig?

Liu

2016-03-15 21:38 GMT-03:00 Carmelo Fruciano :

> Liu Idárraga  ha scritto:
>
>
> Appreciated colleagues.
>> I have some doubts about the correct calculation of error in my data. I
>> had
>> understood that the error corresponde to the proportion that represent the
>> SS of each effect (image / digitalization) in the SStotal; but I found in
>> the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that
>> the
>> way to calculate the percent of the measurement error is:
>>
>> % ME = 100%  s2 within / (s2 within - s2 among)
>>
>> s2 within = MS within
>> but
>> s2 among = (MS among -MS within)/# replicates
>>
>> ​I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 -
>> 18 semi landmarks)
>>
>>
>> Procrustes ANOVA para la forma: con g.l. corregidos
>> Efecto SS SS (%) MS df F p (param.)
>> Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001
>> Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001
>> Digitalización 0,01021206 3,53 1,61175E-06 6336
>> Total 0,28927370 100,00
>>
>> ​My questions are:
>> ​1) Is correct to say that 3,63 and 3,53 are the errors of image and
>> digitalization?
>> 2)  Is the total error equal to 3,63 + 3,53 or I should calculate it with
>> the equations of Bayley & Byrnes 1990?
>>
>> In advance, thanks a lot for the help.
>>
>> Liu
>>
>
> Dear Liu,
> Perhaps the best way to report this would be to say that 3.63% of the
> total sum of squares is accounted for by/due to a certain term
> (digitization, preparation)?
> Best,
> Carmelo
>
>
>
> --
> Carmelo Fruciano
> Postdoctoral Fellow - Queensland University of Technology - Brisbane,
> Australia
> Honorary Fellow - University of Catania - Catania, Italy
> e-mail c.fruci...@unict.it
> http://www.fruciano.it/research/
>
> --
> MORPHMET may be accessed via its webpage at http://www.morphometrics.org
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>
>


-- 
*Liu Idárraga*
Estudiante doctoral
Facultad de Ciencias Naturales y Museo
Universidad de La Plata - Argentina

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Re: [MORPHMET] Doubts about Error Measurement

2016-03-15 Thread Carmelo Fruciano

Liu Idárraga  ha scritto:


Appreciated colleagues.
I have some doubts about the correct calculation of error in my data. I had
understood that the error corresponde to the proportion that represent the
SS of each effect (image / digitalization) in the SStotal; but I found in
the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that the
way to calculate the percent of the measurement error is:

% ME = 100%  s2 within / (s2 within - s2 among)

s2 within = MS within
but
s2 among = (MS among -MS within)/# replicates

​I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 -
18 semi landmarks)


Procrustes ANOVA para la forma: con g.l. corregidos
Efecto SS SS (%) MS df F p (param.)
Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001
Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001
Digitalización 0,01021206 3,53 1,61175E-06 6336
Total 0,28927370 100,00

​My questions are:
​1) Is correct to say that 3,63 and 3,53 are the errors of image and
digitalization?
2)  Is the total error equal to 3,63 + 3,53 or I should calculate it with
the equations of Bayley & Byrnes 1990?

In advance, thanks a lot for the help.

Liu


Dear Liu,
Perhaps the best way to report this would be to say that 3.63% of the  
total sum of squares is accounted for by/due to a certain term  
(digitization, preparation)?

Best,
Carmelo



--
Carmelo Fruciano
Postdoctoral Fellow - Queensland University of Technology - Brisbane,  
Australia

Honorary Fellow - University of Catania - Catania, Italy
e-mail c.fruci...@unict.it
http://www.fruciano.it/research/

--
MORPHMET may be accessed via its webpage at http://www.morphometrics.org
--- 
You received this message because you are subscribed to the Google Groups "MORPHMET" group.

To unsubscribe from this group and stop receiving emails from it, send an email 
to morphmet+unsubscr...@morphometrics.org.



[MORPHMET] Doubts about Error Measurement

2016-03-15 Thread Liu Idárraga
Appreciated colleagues.
I have some doubts about the correct calculation of error in my data. I had
understood that the error corresponde to the proportion that represent the
SS of each effect (image / digitalization) in the SStotal; but I found in
the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that the
way to calculate the percent of the measurement error is:

% ME = 100%  s2 within / (s2 within - s2 among)

s2 within = MS within
but
s2 among = (MS among -MS within)/# replicates

​I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 -
18 semi landmarks)


Procrustes ANOVA para la forma: con g.l. corregidos
Efecto SS SS (%) MS df F p (param.)
Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001
Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001
Digitalización 0,01021206 3,53 1,61175E-06 6336
Total 0,28927370 100,00

​My questions are:
​1) Is correct to say that 3,63 and 3,53 are the errors of image and
digitalization?
2)  Is the total error equal to 3,63 + 3,53 or I should calculate it with
the equations of Bayley & Byrnes 1990?

In advance, thanks a lot for the help.

Liu


-- 
*Liu Idárraga*
Estudiante doctoral
Facultad de Ciencias Naturales y Museo
Universidad de La Plata - Argentina

-- 
MORPHMET may be accessed via its webpage at http://www.morphometrics.org
--- 
You received this message because you are subscribed to the Google Groups 
"MORPHMET" group.
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