Re: [MORPHMET] Doubts about Error Measurement
And respect to the total error, the sum of the % SSimage + % SSdig? Liu 2016-03-15 21:38 GMT-03:00 Carmelo Fruciano: > Liu Idárraga ha scritto: > > > Appreciated colleagues. >> I have some doubts about the correct calculation of error in my data. I >> had >> understood that the error corresponde to the proportion that represent the >> SS of each effect (image / digitalization) in the SStotal; but I found in >> the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that >> the >> way to calculate the percent of the measurement error is: >> >> % ME = 100% s2 within / (s2 within - s2 among) >> >> s2 within = MS within >> but >> s2 among = (MS among -MS within)/# replicates >> >> I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 - >> 18 semi landmarks) >> >> >> Procrustes ANOVA para la forma: con g.l. corregidos >> Efecto SS SS (%) MS df F p (param.) >> Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001 >> Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001 >> Digitalización 0,01021206 3,53 1,61175E-06 6336 >> Total 0,28927370 100,00 >> >> My questions are: >> 1) Is correct to say that 3,63 and 3,53 are the errors of image and >> digitalization? >> 2) Is the total error equal to 3,63 + 3,53 or I should calculate it with >> the equations of Bayley & Byrnes 1990? >> >> In advance, thanks a lot for the help. >> >> Liu >> > > Dear Liu, > Perhaps the best way to report this would be to say that 3.63% of the > total sum of squares is accounted for by/due to a certain term > (digitization, preparation)? > Best, > Carmelo > > > > -- > Carmelo Fruciano > Postdoctoral Fellow - Queensland University of Technology - Brisbane, > Australia > Honorary Fellow - University of Catania - Catania, Italy > e-mail c.fruci...@unict.it > http://www.fruciano.it/research/ > > -- > MORPHMET may be accessed via its webpage at http://www.morphometrics.org > ---You received this message because you are subscribed to the Google > Groups "MORPHMET" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to morphmet+unsubscr...@morphometrics.org. > > -- *Liu Idárraga* Estudiante doctoral Facultad de Ciencias Naturales y Museo Universidad de La Plata - Argentina -- MORPHMET may be accessed via its webpage at http://www.morphometrics.org --- You received this message because you are subscribed to the Google Groups "MORPHMET" group. To unsubscribe from this group and stop receiving emails from it, send an email to morphmet+unsubscr...@morphometrics.org.
Re: [MORPHMET] Doubts about Error Measurement
Liu Idárragaha scritto: Appreciated colleagues. I have some doubts about the correct calculation of error in my data. I had understood that the error corresponde to the proportion that represent the SS of each effect (image / digitalization) in the SStotal; but I found in the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that the way to calculate the percent of the measurement error is: % ME = 100% s2 within / (s2 within - s2 among) s2 within = MS within but s2 among = (MS among -MS within)/# replicates I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 - 18 semi landmarks) Procrustes ANOVA para la forma: con g.l. corregidos Efecto SS SS (%) MS df F p (param.) Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001 Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001 Digitalización 0,01021206 3,53 1,61175E-06 6336 Total 0,28927370 100,00 My questions are: 1) Is correct to say that 3,63 and 3,53 are the errors of image and digitalization? 2) Is the total error equal to 3,63 + 3,53 or I should calculate it with the equations of Bayley & Byrnes 1990? In advance, thanks a lot for the help. Liu Dear Liu, Perhaps the best way to report this would be to say that 3.63% of the total sum of squares is accounted for by/due to a certain term (digitization, preparation)? Best, Carmelo -- Carmelo Fruciano Postdoctoral Fellow - Queensland University of Technology - Brisbane, Australia Honorary Fellow - University of Catania - Catania, Italy e-mail c.fruci...@unict.it http://www.fruciano.it/research/ -- MORPHMET may be accessed via its webpage at http://www.morphometrics.org --- You received this message because you are subscribed to the Google Groups "MORPHMET" group. To unsubscribe from this group and stop receiving emails from it, send an email to morphmet+unsubscr...@morphometrics.org.
[MORPHMET] Doubts about Error Measurement
Appreciated colleagues. I have some doubts about the correct calculation of error in my data. I had understood that the error corresponde to the proportion that represent the SS of each effect (image / digitalization) in the SStotal; but I found in the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that the way to calculate the percent of the measurement error is: % ME = 100% s2 within / (s2 within - s2 among) s2 within = MS within but s2 among = (MS among -MS within)/# replicates I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 - 18 semi landmarks) Procrustes ANOVA para la forma: con g.l. corregidos Efecto SS SS (%) MS df F p (param.) Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001 Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001 Digitalización 0,01021206 3,53 1,61175E-06 6336 Total 0,28927370 100,00 My questions are: 1) Is correct to say that 3,63 and 3,53 are the errors of image and digitalization? 2) Is the total error equal to 3,63 + 3,53 or I should calculate it with the equations of Bayley & Byrnes 1990? In advance, thanks a lot for the help. Liu -- *Liu Idárraga* Estudiante doctoral Facultad de Ciencias Naturales y Museo Universidad de La Plata - Argentina -- MORPHMET may be accessed via its webpage at http://www.morphometrics.org --- You received this message because you are subscribed to the Google Groups "MORPHMET" group. To unsubscribe from this group and stop receiving emails from it, send an email to morphmet+unsubscr...@morphometrics.org.