And respect to the total error, the sum of the % SSimage + % SSdig?
Liu
2016-03-15 21:38 GMT-03:00 Carmelo Fruciano <c.fruci...@unict.it>:
> Liu Idárraga <liuidarr...@gmail.com> ha scritto:
>
>
> Appreciated colleagues.
>> I have some doubts about the correct calculation of error in my data. I
>> had
>> understood that the error corresponde to the proportion that represent the
>> SS of each effect (image / digitalization) in the SStotal; but I found in
>> the classical paper of Bayley & Byrnes 1990. Syst. Zool. 39(2):126 that
>> the
>> way to calculate the percent of the measurement error is:
>>
>> % ME = 100% s2 within / (s2 within - s2 among)
>>
>> s2 within = MS within
>> but
>> s2 among = (MS among -MS within)/# replicates
>>
>> I have the followed results for 71 ind in 2D, and 44 coord (66 - 4 -
>> 18 semi landmarks)
>>
>>
>> Procrustes ANOVA para la forma: con g.l. corregidos
>> Efecto SS SS (%) MS df F p (param.)
>> Individuo0,26857296 92,84 8,59709E-05 3124 25,97 <.0001
>> Imagen 0,01048868 3,63 3,31082E-06 3168 2,05 <.0001
>> Digitalización 0,01021206 3,53 1,61175E-06 6336
>> Total 0,28927370 100,00
>>
>> My questions are:
>> 1) Is correct to say that 3,63 and 3,53 are the errors of image and
>> digitalization?
>> 2) Is the total error equal to 3,63 + 3,53 or I should calculate it with
>> the equations of Bayley & Byrnes 1990?
>>
>> In advance, thanks a lot for the help.
>>
>> Liu
>>
>
> Dear Liu,
> Perhaps the best way to report this would be to say that 3.63% of the
> total sum of squares is accounted for by/due to a certain term
> (digitization, preparation)?
> Best,
> Carmelo
>
>
>
> --
> Carmelo Fruciano
> Postdoctoral Fellow - Queensland University of Technology - Brisbane,
> Australia
> Honorary Fellow - University of Catania - Catania, Italy
> e-mail c.fruci...@unict.it
> http://www.fruciano.it/research/
>
> --
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*Liu Idárraga*
Estudiante doctoral
Facultad de Ciencias Naturales y Museo
Universidad de La Plata - Argentina
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