Grant Edwards wrote:
uint32_t r;
void foo(uint16_t u1, uint16_t u2)
{
r = (uint32_t)u1 * (uint32_t)u2;
}
This will result in a 32x32 Bit Multiplication with the result cropped
to 32 Bits.
Try:
r = (uint32_t)u1 * u2;
Smart compilers will then recognize, that you are demand
> From: Grant Edwards
> Newsgroups: gmane.comp.hardware.texas-instruments.msp430.gcc.user
> Subject: Question about libgcc 16x16=>32 multiply
> Date: Thu, 22 Mar 2007 20:23:28 + (UTC)
Hallo.
> uint32_t r;
>
> void foo(uint16_t u1, uint16_t u2)
> {
> r = (uint32_t)u1 * (uint32_t
> From: John Pitney
> Newsgroups: gmane.comp.hardware.texas-instruments.msp430.gcc.user
> Subject: Building mspgcc on Ubuntu x86_64
> Date: Sat, 17 Mar 2007 19:57:16 -0500
> Hi,
>
> I'm having a problem compiling mspgcc on my Ubuntu 6.06 x86_64 system.
There are two relatively new deb reposito
uint32_t r;
void foo(uint16_t u1, uint16_t u2)
{
r = (uint32_t)u1 * (uint32_t)u2;
}
I've been looking at the code for the case above:
1 foo:
2 pushr11
3 pushr10
4 mov r15, r10
5 mov r14, r12
6
