/\/\ark wrote: >This, however, is not the correct routine. It should be, as I >suggested by replacing x:=sqr(x) by x:=x*x, as followed: > [snip] > >As you see, with x:=sqr(x) x goes from x to x^0.5 to x^0.25... With >x:=x*x, however, your statement does hold for x goes from x to x^2 to x^4... Sorry Mark, you're definitely wrong: Sqr (x) == x^2 Sqrt(x) == x^.5 A small, but important difference :-) Eric (it's no biggy ;-)) **** MSX Mailinglist. To unsubscribe, send an email to [EMAIL PROTECTED] and put in the body (not subject) "unsubscribe msx [EMAIL PROTECTED]" (without the quotes :-) Problems? contact [EMAIL PROTECTED] (www.stack.nl/~wiebe/mailinglist/) ****