/Ian wrote:
Every time you modify the filter coefficients, modify the state of the//filter
so that it will produce the output you are expecting. Easy to do.
/Ethan wrote:
A very simple oscillator recipe is [the coupled form]. However, it's not stable
as is, so you periodically have to make an a
>/ > well, pink is -3 dB/octave and red (a.k.a. brown) is -6 dB/octave. a
/
>/ > roll-off of -12// dB/octave would be very brown. -- r b-j
/
>/ Those values are for amplitudes - for a power spectrum the slopes double.
/
no sir. not with dB. this is why we use
dB = 20 * log10(ampli
> well, pink is -3 dB/octave and red (a.k.a. brown) is -6 dB/octave. a
roll-off of -12
> dB/octave would be very brown. -- r b-j
Those values are for amplitudes - for a power spectrum the slopes double.
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Am 16.11.2015 20:00, schrieb Martin Vicanek:
[..] the autocorrelation is
= (1/3)*(1-P)^|k|
(I checked that with a little MC code before posting.) So the power
spectrum is (1/3)/(1 + (1-P)z^-1), i.e flat at DC and pink at higher
frequencies. For reasonably small P the corner frequency is
Has this been answered yet? If not, I'll try a back-of-the-envelope
derivation.
Consider two consecutive samples. By definition, the probability for
them to be equal is (1-P), else they will be different and perfectly
uncorrelated. Hence the expected correlation between two consecutive
sample
In my previous post please substitute "omega" for "?". Sorry for the
mess, my first post.
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Some thoughts regarding Vadim's original question (I am considering
periodic signals in continuous time domain). Discontinuities in the time
domain result in infinite bandwidth, but is the reverse also true?
1. Is a waveform band limited, if all its derivatives are continuous?
Answer is: no, a
