The problem I see is that your sine wave needs to have a precise
amplitude for the arcsine.
I don't understand your application so I don't know if this is the case.
Am 09.03.2018 um 19:58 schrieb Benny Alexandar:
Hi GM,
Instead of finding Hilbert transform, I tried with just finding the
Hi ben
You don't need to evaluate the asin() - it's piecewise monotonic and
symmetrical, so you can get the same comparison directly in the signal
domain.
Specifically, notice that x(n) = sin(2*pi*(1/4)*n) = [...0,1,0,-1,...]. So
you get the same result just by checking ( abs( x[n] - x[n-1] ) ==
Hi GM,
My application is to capture an analog sine tone through PC sound card and
check for discontinuity, glitch, audio gap, attenuation etc.
Please suggest any other reliable methods for this analysis.
-ben
From: music-dsp-boun...@music.columbia.edu
