Hi,
I searching for a database, with the 'complete' world Countries, cities,
states
Just like http://www.datingplace.com/servlet/NewRegistration
I need for an academic study.
Thanks,
Augusto
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HelpHi.
I'm using the timestamp format (AAMMDDHHMMSS) on my session.
how can I know the minutes between two dates.
I'm doing:
=20
$date =3D $row_secao['date'];
$date_now=3Ddate(ymdHis); =20
$x=3D$date_atual-$date;
if ($x 1000) {
echo Session
HelpHi.
I have a colun in my table for the birthday.: DD/MM/. It's varchar.
In PHP, I can get the month of date, bu substr($date, 3, 2). (MM)
Can I do a select with %LIKE% but saying the position of the varchar I want to find?
thanks.
Augusto
It's possible get the number of years between two dates in a mysql
function?
thanks,
Augusto
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How can I know the version of mysql running on Linux (RedHat 6.2)
thanks,
Augusto
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To
I tried to put the data (.frm, .ISD and .ISM files) of my Linux into
windows 98 put I can't use the data. When I open phpadmin2, he show how
many registrys I have, but When I try to use/list the table is empty. Can
I solve this problem? I need to use mysqldump to put the data into windows
98?
How can I transfer the data from a MySQL 3.22.32 running on RedHat
6.2 Linux to a MySQL 2.23.37 running on Windows 98?
thanks,
Augusto
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Before posting, please check:
http://www.mysql.com/manual.php (the manual)
I'm receiving the following error:
Warning: MySQL Connection Failed: Can't connect to local MySQL server
through socket '/tmp/mysql.sock' (111) in
/home/httpd/html/phpadmin2/lib.inc.php on line 119
what could be?
thanks,
Augusto
you can use fetch_array:
$data = mysql_query(select * from Categories);
$aux=select name=categorie;
while ($row = mysql_fetch_array($data)) {
$aux.=option value=,$row['id']..$row['Name']./option;
}
$aux.=/select;
echo $aux;
this code will print in html a combobox with the options, in php,
Let me see if I understood your question:
select * from tablename a, tablename2 b where a.account='BILL' and
a.account=b.account
It's tow tables or just one table?
because if it's just one table just do select * from tablename where
account='BILL'
see you,
Augusto
On Sat, 9 Jun 2001, Jaime
Z , lPi1QzB5%!.dC;@);
I have a in the middle of the encoded string. How can I solve this
problem?
regards,
Augusto Cesar Castoldi
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http
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