Hi There,
Has anyone been successful installing and running MySQL (current
version) on the new Mac OS (Leopard)?
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Craig Hoffman
iChat/AIM: m0untaind0g
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they fix the pref pane.
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Craig Hoffman
iChat/AIM: m0untaind0g
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On Oct 26, 2007, at 3:59 PM, Craig Hoffman wrote:
Hi There,
Has anyone been successful installing and running MySQL (current
version) on the new Mac OS (Leopard
Anyone know a way to convert MS Access DB files (.mdb) into a format
MySQL can import? I'm on a Mac hence I don't have Access.
Best,
CH
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Craig Hoffman
www.eclimb.net
[EMAIL PROTECTED]
iChat / AIM: m0untaind0g
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Thanks - I got it working.
On Jan 18, 2005, at 12:35 AM, Mattias J wrote:
At 2005-01-18 04:53, Craig Hoffman wrote:
I upgrade to 4.1.9 last night and I keep getting this error in
PhpMyAdmin after I changed the root password (yes I changed both
pw's). Does anyone have a solution on how to fix
Hi There,
I have web form where a user can search certain fields and then have
them displayed aggregated. For example, find all the routes I climbed
with partner A in area(s) ALL (% - wildcard) between date1 and date2 --
so on. See below for the complete query.
I'm using pull down menu's and
I upgrade to 4.1.9 last night and I keep getting this error in
PhpMyAdmin after I changed the root password (yes I changed both pw's).
Does anyone have a solution on how to fix this? I'm running a Mac
10.3.x
#1251 - Client does not support authentication protocol requested by
server;
Mark,
Yes its close and thank you. The problem I am having is I am able to
generate the correct ranking.id for that particular user but I can't
seem to make it equal the ranking.rating.
ID ranking.rating
9 = 5.6 (example)
Here's my query:
SELECT routes.user_id, ranking.rating,
Hey Everyone,
I can you some assistance on this query.
I have three tables one is called ranking and the other is called
routes and finally the users table. The users table is not really
important.
The ranking table looks like this:
id rating
1 5.0
2 5.1
3 5.2
4 5.3
Hey Folks,
I have a query where it pulls random data and display's it.
SELECT route_photo, route, route_count, area FROM routes WHERE
ORDER BY RAND() LIMIT 1
The query works fine, however, the route_photo field is partially
populated. This results in just a route name appearing but no
Hey Everyone,
I have query where one selects an style then a area and finally
rating. When some selects a rating they select a range of ratings.
For example:
Style: Traditional
Area: Yosemite
Rating: From: 5.5 To: 5.10c
This should pull up all the rock climbs that are in Yosemite, that are
= 'Traditonal' GROUP BY route ORDER BY id
DESC
Thanks,
Craig
On Jul 9, 2004, at 1:17 PM, Pete Harlan wrote:
On Fri, Jul 09, 2004 at 09:39:02AM -0500, Craig Hoffman wrote:
Style: Traditional
Area: Yosemite
Rating: From: 5.5 To: 5.10c
...
SELECT * FROM routes, users WHERE area='$area' AND style
TURNCATE(AVG(distance)), rest of the query
Thanks - CH
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Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimb.net
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that worked - Thanks a bunch!
CH
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Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimb.net
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On Apr 11, 2004, at 3:14 PM, Mike Blezien wrote:
I think your looking for the ROUND(N,D
.
__
Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimb.net
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Yes your right - I thought the numbers in the DB were something else.
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Craig Hoffman - eClimb Media
v: (847) 644 - 8914
f: (847) 866 - 1946
e: [EMAIL PROTECTED]
w: www.eclimb.net
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On Apr 2, 2004, at 11:11 AM, Paul DuBois wrote
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