Is there a way to update random records?
I have a database of 5.6 million records and I want to pull out 5000
records and mark a field in the database that I've pulled these so that I
don't pull the same 5000 again.
I know I can select the records by doing:
SELECT * FROM 5600k WHERE picked IS
I have a database of 5.6 million records and I need to choose 5000 random
records. What would that query look like?
-
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com/
Pretty much was Siomara says is the way I think, except that I would have
made the extra table for the two addresses. For the kids field it depends
on what you want. If you want to have information for each child then you
would create a separate table, but if you just need to record the number
I'm curious as to how people are installing MySQL on Linux. I've been
learning linux on Red Hat and more recently I've been using Trustix Secure
Linux (which also uses RPMs) but I've never actually installed MySQL through
the RPM's. The person who gave me my first basic lessons in Linux had an
/articles/ddws/4.html
- Original Message -
From: Roger Ramirez [EMAIL PROTECTED]
To: MySQL [EMAIL PROTECTED]
Sent: Saturday, July 07, 2001 10:02 AM
Subject: RPM or Source or Binary
I'm curious as to how people are installing MySQL on Linux. I've been
learning linux on Red Hat and more
Why do I get the following results?
mysql select (1008306000-988344000)/86400/7,
mod((1008306000-988344000)/86400,7.);
++--
+
| (1008306000-988344000)/86400/7 | mod((1008306000-988344000)/86400,7.)
|
You can use:
SELECT Column_Name, count(Column_Name) FROM Table_Name GROUP BY
Column_Name
-Original Message-
From: Franz, Fa. PostDirekt MA [mailto:[EMAIL PROTECTED]]
Sent: Friday, February 16, 2001 3:02 AM
To: [EMAIL PROTECTED]
Subject: COUNT(DISTINCT Column_Name)
Hi Everybody
something like WHERE
count(member_id) 1 (although I know this does not work in that query)
Thanks,
Roger Ramirez
Senior Developer
TodoBebe.com - Todo lo que quiere saber de su beb.
TodoBebe.com - The best baby website in Spanish!
www.todobebe.com
Duh why didn't I think of that.
Thank you graciously. :)
-Original Message-
From: Quentin Bennett [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 15, 2001 4:26 PM
To: 'Roger Ramirez'; MySQL List
Subject: RE: Query/Left Join problem
Hi,
Your left join tried to find members
I copied and pasted your create table query into mysql and it created the
table without a problem. I'm using 3.32.32.
mysql describe top
- ;
+-+---+--+-+-++
| Field | Type | Null | Key | Default | Extra |
Try using this function on your data before inserting into the database.
http://www.php.net/manual/en/function.addslashes.php
If that doesn't work show us what error you are getting.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Monday, February 05,
Couldn't you just do:
boolVarsENUM ('True', 'False') DEFAULT 'False'
-or-
boolVarsENUM ('TRUE', 'FALSE') DEFAULT 'FALSE'
unless I'm misunderstanding what you are saying about ASP.
-Original Message-
From: Russ Davies [mailto:[EMAIL PROTECTED]]
Sent: Tuesday,
Use your own id's. I personally hate auto increment. I do all my work in
php so I make my id's like this.
srand(time());
$id = md5(uniqid(rand()));
This will make a 32 character id.
-Original Message-
From: Viken Nokhoudian [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, January 30,
Hmmm... Looks like you over did the query to me. This should work.
SELECT o.OrderID, c.CustomerFirst, c.CustomerLast, s.SalesRepFirst,
s.SalesRepLast
FROM Orders as o, Customers as C, SalesReps as s
WHERE O.CustomerPhone=c.CustomerPhone AND o.SalesRepID=s.SalesRepID
of course you don't need
14 matches
Mail list logo
