Hi,
>SELECT TD.project_id, P.project_manager
>FROM time_daily TD
>INNER JOIN projects P ON P.project_id = TD.time_project_id
>WHERE TD.time_user_id = 'xpt' AND (
>SUM( TD.time_hours_worked ) <> '0.00'
an Paul Dibois said:
You cannot use aggregate functions like SUM() in the WHERE clause.
And He i
Hi!
Try this:
SELECT TD.project_id, P.project_manager,
SUM( TD.time_hours_worked ) as hours
FROM time_daily TD
INNER JOIN projects P ON P.project_id = TD.time_project_id
WHERE TD.time_user_id = 'xpt'
HAVING hours <> '0.00'
Hope this helps!
On Wed, 2003-09-03 at 17:24, Cory Hicks wrote:
Hi,
Paul DuBois said:
> At 11:24 -0500 9/3/03, Cory Hicks wrote:
>>Hey folks,
>>
>>I am trying to run the following sql query in mysql:
>>
>>SELECT TD.project_id, P.project_manager
>>FROM time_daily TD
>>INNER JOIN projects P ON P.project_id = TD.time_project_id
>>WHERE TD.time_user_id = 'xpt' AND
Sorry,
I think it should be
GROUP BY TD.project_id, P.project_manager
Cory Hicks said:
> Hey folks,
>
> I am trying to run the following sql query in mysql:
>
> SELECT TD.project_id, P.project_manager
> FROM time_daily TD
> INNER JOIN projects P ON P.project_id = TD.time_project_id
> WHERE TD.
Cory,
Cory Hicks said:
> Hey folks,
>
> I am trying to run the following sql query in mysql:
>
> SELECT TD.project_id, P.project_manager
> FROM time_daily TD
> INNER JOIN projects P ON P.project_id = TD.time_project_id
> WHERE TD.time_user_id = 'xpt' AND (
> SUM( TD.time_hours_worked ) <> '0.00'
>
At 11:24 -0500 9/3/03, Cory Hicks wrote:
Hey folks,
I am trying to run the following sql query in mysql:
SELECT TD.project_id, P.project_manager
FROM time_daily TD
INNER JOIN projects P ON P.project_id = TD.time_project_id
WHERE TD.time_user_id = 'xpt' AND (
SUM( TD.time_hours_worked ) <> '0.00'
Hey folks,
I am trying to run the following sql query in mysql:
SELECT TD.project_id, P.project_manager
FROM time_daily TD
INNER JOIN projects P ON P.project_id = TD.time_project_id
WHERE TD.time_user_id = 'xpt' AND (
SUM( TD.time_hours_worked ) <> '0.00'
)
And I keep getting the # errno