] can you nest functions? problems with data
types
I can simplify this even more..
I have this
${position}
This outputs 135 for the echo
But when I try
${position - 3}
It considers position a string, not an int. Without the outside ${ }
its not an expression. How do I
teve Kapinos; 'Ron Grabowski'; 'nant'
Subject: RE: [NAnt-users] can you nest functions? problems with data
types
Hey Steve,
Use int::parse instead.
Gert
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Steve
Kapinos
Sent: zondag 14 septe
Hey Steve,
Use int::parse instead.
Gert
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Steve Kapinos
Sent: zondag 14 september 2008 6:19
To: Ron Grabowski; nant
Subject: Re: [NAnt-users] can you nest functions? problems with data types
It's not r
his convert function.
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Ron
Grabowski
Sent: Saturday, September 13, 2008 11:58 PM
To: nant
Subject: Re: [NAnt-users] can you nest functions? problems with data
types
It looks like you're doing some serious manipul
[NAnt-users] can you nest functions? problems with data types
I can simplify this even more..
I have this
${position}
This outputs 135 for the echo
But when I try
${position - 3}
It considers position a string, not an int. Without the outside ${ }
its not an expression. How do
subtract 3 from it?
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Steve
Kapinos
Sent: Saturday, September 13, 2008 11:13 PM
To: nant-users@lists.sourceforge.net
Subject: [NAnt-users] can you nest functions? problems with data types
Ok, I'm trying to
Ok, I'm trying to do some simple expressions to manipulate some values,
but I'm not having luck nesting expressions. Specifically, I can not
figure out how to use a function as a argument to another function.
This means I have to use incremental steps and assign the value to a
property, then refer
