protected methods of super class are made public in the generated script
subclass. Java.super should have worked. If you can submit a simpler
test case, it may be possible to see what's happening..
Thanks
-Sundar
On 02/10/18, 3:52 PM, Axel Dörfler wrote:
Hi Sundar,
Am 01/10/2018 um 05:00
Hi Sundar,
Am 01/10/2018 um 05:00 schrieb Sundararajan Athijegannathan:
In your example, it seems you're trying to add a new method to the
subtype created in script. That is not supported. You can override
existing methods of superclass - but not add a new method to the Java
type.
Bummer!
Hi,
In your example, it seems you're trying to add a new method to the
subtype created in script. That is not supported. You can override
existing methods of superclass - but not add a new method to the Java
type. Note that all super methods (including protected ones) are
available via
Am 28/09/2018 um 11:34 schrieb Sundararajan Athijegannathan:
It is hard to say what went wrong without looking at your full sample/test.
Openjdk wiki page explains Java.extend function is here:
http://hg.openjdk.java.net/jdk/jdk/file/7bd8d6b011c9/src/sample/nashorn/resourcetrysuggester.js
Hi there,
I'm trying to extend an Abstract java base class, and add a new method
to it. However, that doesn't seem to work.
I've tried it like this:
var object = Java.extend(MyType, {
newFunction: function(argument) {
...
}
});
And that:
MyType.newFunction =
