Re: [RFC] bmac:change to use bitrev8() generic function

2015-08-10 Thread yalin wang

 On Aug 10, 2015, at 20:02, David Laight david.lai...@aculab.com wrote:
 
 From: Tobias Klauser
 Sent: 10 August 2015 12:49
 On 2015-08-10 at 11:53:41 +0200, yalin wang yalin.wang2...@gmail.com wrote:
 This change to use generic bitrev8() for bmac driver.
 ...
 @@ -871,7 +860,7 @@ bmac_addhash(struct bmac_data *bp, unsigned char *addr)
 
 if (!(*addr)) return;
 crc = bmac_crc((unsigned short *)addr)  0x3f; /* Big-endian alert! */
 
 Why not *((u8 *)addr + 1)  0x3f
 
 -   crc = reverse6[crc];/* Hyperfast bit-reversing algorithm */
 +   crc = bitrev8((u8)crc);
 
 No, this won't work. reverse6 works on 6 bit values, while bitrev8 works
 on 8bit values, e.g. reverse6[1] = 0x20, while bitrev8(1) = 0x80
 
 You could use bitrev8(n)  2.
 
 But that is a 'strange' map of a 7-bit value to a 6-bit one.
 
 I thought it was more common for ethernet hardware to use the
 value of the crc register after all 6 bytes of the mac address
 had been processed.
oh, my mistake, i will change it in V2 for review.--
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Re: [RFC] bmac:change to use bitrev8() generic function

2015-08-10 Thread Tobias Klauser
On 2015-08-10 at 11:53:41 +0200, yalin wang yalin.wang2...@gmail.com wrote:
 This change to use generic bitrev8() for bmac driver.
 
 Signed-off-by: yalin wang yalin.wang2...@gmail.com
 ---
  drivers/net/ethernet/apple/bmac.c | 17 +++--
  1 file changed, 3 insertions(+), 14 deletions(-)
 
 diff --git a/drivers/net/ethernet/apple/bmac.c 
 b/drivers/net/ethernet/apple/bmac.c
 index a65d7a6..e749747 100644
 --- a/drivers/net/ethernet/apple/bmac.c
 +++ b/drivers/net/ethernet/apple/bmac.c
 @@ -22,6 +22,7 @@
  #include linux/bitrev.h
  #include linux/ethtool.h
  #include linux/slab.h
 +#include linux/bitrev.h
  #include asm/prom.h
  #include asm/dbdma.h
  #include asm/io.h
 @@ -805,18 +806,6 @@ static irqreturn_t bmac_txdma_intr(int irq, void *dev_id)
  }
  
  #ifndef SUNHME_MULTICAST
 -/* Real fast bit-reversal algorithm, 6-bit values */
 -static int reverse6[64] = {
 - 0x0,0x20,0x10,0x30,0x8,0x28,0x18,0x38,
 - 0x4,0x24,0x14,0x34,0xc,0x2c,0x1c,0x3c,
 - 0x2,0x22,0x12,0x32,0xa,0x2a,0x1a,0x3a,
 - 0x6,0x26,0x16,0x36,0xe,0x2e,0x1e,0x3e,
 - 0x1,0x21,0x11,0x31,0x9,0x29,0x19,0x39,
 - 0x5,0x25,0x15,0x35,0xd,0x2d,0x1d,0x3d,
 - 0x3,0x23,0x13,0x33,0xb,0x2b,0x1b,0x3b,
 - 0x7,0x27,0x17,0x37,0xf,0x2f,0x1f,0x3f
 -};
 -
  static unsigned int
  crc416(unsigned int curval, unsigned short nxtval)
  {
 @@ -871,7 +860,7 @@ bmac_addhash(struct bmac_data *bp, unsigned char *addr)
  
   if (!(*addr)) return;
   crc = bmac_crc((unsigned short *)addr)  0x3f; /* Big-endian alert! */
 - crc = reverse6[crc];/* Hyperfast bit-reversing algorithm */
 + crc = bitrev8((u8)crc);

No, this won't work. reverse6 works on 6 bit values, while bitrev8 works
on 8bit values, e.g. reverse6[1] = 0x20, while bitrev8(1) = 0x80
--
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RE: [RFC] bmac:change to use bitrev8() generic function

2015-08-10 Thread David Laight
 From: Tobias Klauser
 Sent: 10 August 2015 12:49
 On 2015-08-10 at 11:53:41 +0200, yalin wang yalin.wang2...@gmail.com wrote:
  This change to use generic bitrev8() for bmac driver.
...
  @@ -871,7 +860,7 @@ bmac_addhash(struct bmac_data *bp, unsigned char *addr)
 
  if (!(*addr)) return;
  crc = bmac_crc((unsigned short *)addr)  0x3f; /* Big-endian alert! */

Why not *((u8 *)addr + 1)  0x3f

  -   crc = reverse6[crc];/* Hyperfast bit-reversing algorithm */
  +   crc = bitrev8((u8)crc);
 
 No, this won't work. reverse6 works on 6 bit values, while bitrev8 works
 on 8bit values, e.g. reverse6[1] = 0x20, while bitrev8(1) = 0x80

You could use bitrev8(n)  2.

But that is a 'strange' map of a 7-bit value to a 6-bit one.

I thought it was more common for ethernet hardware to use the
value of the crc register after all 6 bytes of the mac address
had been processed.

David

--
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