Hi all,
args1=one two
args2=three four
$ mycommand one two three four
You passed 4 arguments
- one
- two
- three
- fout
$ mycommand $args1 $args2
You passed 2 arguments
- one two
- three four
How can I pass args1 and args2 to mycommand as 4 arguments?
I think in bash, this script might get run
Hi,
On 02/04/12 23:28, Mathijs Kwik wrote:
args1=one two
args2=three four
...
$ mycommand $args1 $args2
You passed 2 arguments
Eh? Unless you have set $IFS to a non-standard value, $args1 and $args2 will be
split into four arguments.
--
Eelco Dolstra |
Yeah, that's OT.
on irc there is #bash which should be the source of knowledge to gather
some keywords. Nevertheless here is your solution
First get a test script (copy paste into your bash shell):
args1=one two
args2=three four
sh -c 'for x in $@; do echo arg: $x; done' -- $args1 $args2
it
On Mon, Apr 2, 2012 at 11:33 PM, Eelco Dolstra
eelco.dols...@logicblox.com wrote:
Hi,
On 02/04/12 23:28, Mathijs Kwik wrote:
args1=one two
args2=three four
...
$ mycommand $args1 $args2
You passed 2 arguments
Eh? Unless you have set $IFS to a non-standard value, $args1 and $args2 will
On Mon, Apr 2, 2012 at 11:42 PM, Marc Weber marco-owe...@gmx.de wrote:
Yeah, that's OT.
on irc there is #bash which should be the source of knowledge to gather
some keywords. Nevertheless here is your solution
First get a test script (copy paste into your bash shell):
args1=one two
args1=one two
args2=three four
...
$ mycommand $args1 $args2
You passed 2 arguments
Eh? Unless you have set $IFS to a non-standard value, $args1 and $args2
will be
split into four arguments.
Ah, my bad.
It seems bash and sh work fine, my zsh seems to be the problem.
I blindly assumed
Ah, that's it then. it seems ${=foo} doesn't do the trick in zsh
either though, but I don't care. It's not the target, I just tried it
there.
In general use a scripting language (ruby/python/perl/tcl/..) for
everything more complicated. bash starts to be a bottle neck very soon
(example is
