Indeed it seems like the alignment is good with \dfrac, but this does
not solve my problem, since I wish to also use fractions with
script-size or scriptscript-size (\xfrac, \xxfrac). The specific
formula I have is
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t

Le 28 janv. 13 à 10:11, Janne Junnila a écrit :
Indeed it seems like the alignment is good with \dfrac, but this does
not solve my problem, since I wish to also use fractions with
script-size or scriptscript-size (\xfrac, \xxfrac). The specific
formula I have is
\startformula
f_{B_t | B_s = S

On Mon, 28 Jan 2013, Roland Thiers wrote:
Le 28 janv. 13 à 10:11, Janne Junnila a écrit :
Indeed it seems like the alignment is good with \dfrac, but this does
not solve my problem, since I wish to also use fractions with
script-size or scriptscript-size (\xfrac, \xxfrac). The specific

with
script-size or scriptscript-size (\xfrac, \xxfrac). The specific
formula I have is
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s))^2}{(u-s)}}{2(t-s)(u-t)}}}{\sqrt{2\pi\frac{(t-s)(u-t)}{u-s}}}
\stopformula
Thanks,
Janne

with \dfrac, but this does
not solve my problem, since I wish to also use fractions with
script-size or scriptscript-size (\xfrac, \xxfrac). The specific
formula I have is
\startformula
f_{B_t | B_s = S, B_u = U}(x) = \frac{e^{-\frac{(u-s)x^2 - 2x(S(u-t) +
U(t-s)) + \frac{(S(u-t) +
U(t-s