[NTG-context] Split \startalign content on more pages

2012-05-21 Thread elgo...@libero.it
Thank you Luigi.
I haven't tried your solution yet, as I was abroad the previous days.
I hope I will try later.
Bye.

Arrigo
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[NTG-context] Split \startalign content on more pages

2012-05-14 Thread elgo...@libero.it
Yes it works.
The only problem is that now I have the formulas aligned at the center of the 
page.
Which command can I use to align the formulas on the left?

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[NTG-context] Split \startalign content on more pages

2012-05-13 Thread elgo...@libero.it
\sbc{} is a command defined by me.
\define[1]\sbc{\ctxlua{context(\%.2f, #1)}}%
I'm writing a technical report and I use that command to substitute numbers to 
letters in formulas.

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[NTG-context] Split \startalign content on more pages

2012-05-13 Thread elgo...@libero.it
Sorry for having given you a non working example!
Here you can find a working one. The comments at the end of each line are in 
italian. 
Changing the height of the frame you can move the \startalign content in the 
page.
As you will see, the whole content flows from one page to the following, 
without splitting at the right line.
Thank you very much for your help.



%INIZIO PREAMBOLO
\setuppapersize[A4, portrait] [A4]% layout di pagina su foglio A4
\setuplayout[width=middle]% disposizione del testo sulla pagina
\setuppagenumbering[location={footer, middle}]% numero di pagina in basso al 
centro
\setupbodyfont[11pt]% altezza carattere 11pt
\setupcolors[state=start, rgb=yes]% per usare colori
\setupcolor[rgb]% carico colori di default
\setuptabulate[split=yes]% consente di spezzare le liste di tabualte su più 
pagine
%\setupindenting[medium, yes]% indentazione prima linea di paragrafi
\mainlanguage[it]% lingua principale del documento
\usemodule[units]% per scrivere le unità di misura in maniera coerente sia in 
modalità testo che matematico
%\usemodule[NTE]% per crare le tabelle complesse multipagina utilizzando 
l'ambiente TABLE
%
%--COMANDI DEFINITI DA UTENTE-
% comando \sb
\def\sb#1{\ctxlua{tex.print(#1)}}% definizione comando di sostituzione dei 
valori numerici a quelli letterali
% comando \sba
\def\sba#1{\ctxlua{tex.print(string.format(\%.0f, #1))}}% sostituisce numero 
a valori letterali scrivendolo senza cifre decimali
% comando \sbb
\define[1]\sbb{\ctxlua{context(\%.1f, #1)}}% sostituisce numero a valori 
letterali scrivendolo con 1 cifra decimale
% comando \sbc
\define[1]\sbc{\ctxlua{context(\%.2f, #1)}}% sostituisce numero a valori 
letterali scrivendolo con 2 cifre decimali
% comando \sbd
\define[1]\sbd{\ctxlua{context(\%.3f, #1)}}% sostituisce numero a valori 
letterali scrivendolo con 3 cifre decimali

\definedescription[descr][style=packed,headstyle=bold,style=normal,
location=hanging,width=broad,margin=1cm]
%FINE PREAMBOLO

\starttext
Bla bla bla

{\framed[height=15cm] Bla Bla}




\startluacode
e_yfi=5
R_fi=2000
r_fi=300
D_ifi=2500
P_dfi=0.6
f_dfi=200

e_dtryfi=1 -- spessore di tentativo in progetto in mm
e_yfi=100 -- inizializzo il valore ey a 100
while math.abs(e_yfi-e_dtryfi)0.001 do
e_dtryfi=e_yfi
Y=math.min((e_dtryfi / R_fi), 0.04)
Z=math.log10(1/Y)
X=r_fi/D_ifi
N=1.006-(1 / (6.2+(90*(Y^4
beta006=N*((-0.3635*(Z^3))+(2.2124*(Z^2))-(3.2937*Z)+1.8873)
beta01=N*((-0.1833*(Z^3))+(1.0383*(Z^2))-(1.2943*Z)+0.837)
beta02=math.max(0.95*(0.56-(1.94*Y)-(83.5*(Y^2))), 0.5)
if X==0.06 then
beta=beta006
elseif 0.06X and X0.1 then
beta=25*(((0.1-X)*beta006)+((X-0.06)*beta01))
elseif X==0.1 then
beta=beta01
elseif 0.1X and X0.2 then
beta=10*(((0.2-X)*beta01)+((X-0.1)*beta02))
elseif X==0.2 then
beta=beta02
else tex.print(\\red{ERRORE NELLA GEOMETRIA DEL FONDO INFERIORE})
end
e_yfi=(beta*P_dfi*((0.75*R_fi)+(0.2*D_ifi)))/f_dfi
end

\stopluacode


\setupformulas[align=right]
\startformula
\startalign[n=3, align={left, right, left}]
\NC \text{dove} \quad   \NC Y \NC = min \left({{e_{yfi}} \over {R_{fi}}}; 0.04 
\right) = min \left({{\sbc{e_yfi}} \over {\sba{R_fi}}}; 0.04 \right)=\sbd{Y} 
\NR
\NC \NC Z \NC = log_{10} \left({1 \over Y} 
\right) = log_{10} \left({1 
\over \sbd{Y}} \right) = \sbc{Z} \NR
\NC \NC X \NC = {{r_{fi}} \over {D_{ifi}}} 
= {{\sba{r_fi}} \over {\sba
{D_ifi}}} = \sbd{X} \NR
\NC \NC N \NC = 1.006 - {1 \over {6.2 + 
\left(90 \cdot Y \right)^4}} = 
1.006 - {1 \over {6.2 + \left(90 \cdot \sbd{Y} \right)^4}} = \sbd{N} \NR
\startluacode
if X==0.06 then
tex.print(\\NC  \\NC \\beta_{0.06} \\NC = N \\cdot \\left(-0.3635 
\\cdot Z^3 
+ 2.2124 \\cdot Z^2 - 3.2937 \\cdot Z + 1.8873 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.3635 \\cdot \\sbc{Z}^3 
+ 2.2124 \\cdot \\sbc{Z}^2 - 3.2937 \\cdot \\sbc{Z} + 1.8873 \\right) = \\sbc
{beta006} \\NR)
tex.print(\\NC  \\NC \\beta \\NC =\\beta_{0.06}=\\sbc{beta006} \\NR)
elseif X0.06 and X0.1 then
tex.print(\\NC  \\NC \\beta_{0.06} \\NC = N \\cdot \\left(-0.3635 
\\cdot Z^3 
+ 2.2124 \\cdot Z^2 - 3.2937 \\cdot Z + 1.8873 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.3635 \\cdot \\sbc{Z}^3 
+ 2.2124 \\cdot \\sbc{Z}^2 - 3.2937 \\cdot \\sbc{Z} + 1.8873 \\right) = \\sbc
{beta006} \\NR)
tex.print(\\NC  \\NC \\beta_{0.1} \\NC = N \\cdot \\left(-0.1833 
\\cdot Z^3 
+ 1.0383 \\cdot Z^2 - 1.2943 \\cdot Z + 0.837 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.1833 \\cdot \\sbc{Z}^3 
+ 1.0383 \\cdot \\sbc{Z}^2 - 1.2943 \\cdot \\sbc{Z} + 0.837 \\right) = 

[NTG-context] Split \startalign content on more pages

2012-05-11 Thread elgo...@libero.it
Thank you very much Luigi.

Any idea on how to split the \startalign content?

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[NTG-context] Split \startalign content on more pages

2012-05-10 Thread elgo...@libero.it
Hello,
I'm a new user of context (and of this mailing list).
I'm facing some problems in splitting the \startalign ... \stopalign content 
on more pages.
This is the formulas:

\setupformulas[align=right]
\startformula
\startalign[n=3, align={left, right, left}]
\NC \text{dove} \quad   \NC Y \NC = min \left({{e_{yfitest}} \over {R_{fi}}}; 
0.04 \right) = min \left({{\sbc{e_yfitest}} \over {\sba{R_fi}}}; 0.04 \right)
=\sbd{Y} \NR
\NC \NC Z \NC = log_{10} \left({1 \over Y} 
\right) = log_{10} \left({1 
\over \sbd{Y}} \right) = \sbc{Z} \NR
\NC \NC X \NC = {{r_{fi}} \over {D_{ifi}}} 
= {{\sba{r_fi}} \over {\sba
{D_ifi}}} = \sbd{X} \NR
\NC \NC N \NC = 1.006 - {1 \over {6.2 + 
\left(90 \cdot Y \right)^4}} = 
1.006 - {1 \over {6.2 + \left(90 \cdot \sbd{Y} \right)^4}} = \sbd{N} \NR
\startluacode
if X==0.06 then
tex.print(\\NC  \\NC \\beta_{0.06} \\NC = N \\cdot \\left(-0.3635 
\\cdot Z^3 
+ 2.2124 \\cdot Z^2 - 3.2937 \\cdot Z + 1.8873 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.3635 \\cdot \\sbc{Z}^3 
+ 2.2124 \\cdot \\sbc{Z}^2 - 3.2937 \\cdot \\sbc{Z} + 1.8873 \\right) = \\sbc
{beta006} \\NR)
tex.print(\\NC  \\NC \\beta \\NC =\\beta_{0.06}=\\sbc{beta006} \\NR)
elseif X0.06 and X0.1 then
tex.print(\\NC  \\NC \\beta_{0.06} \\NC = N \\cdot \\left(-0.3635 
\\cdot Z^3 
+ 2.2124 \\cdot Z^2 - 3.2937 \\cdot Z + 1.8873 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.3635 \\cdot \\sbc{Z}^3 
+ 2.2124 \\cdot \\sbc{Z}^2 - 3.2937 \\cdot \\sbc{Z} + 1.8873 \\right) = \\sbc
{beta006} \\NR)
tex.print(\\NC  \\NC \\beta_{0.1} \\NC = N \\cdot \\left(-0.1833 
\\cdot Z^3 
+ 1.0383 \\cdot Z^2 - 1.2943 \\cdot Z + 0.837 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.1833 \\cdot \\sbc{Z}^3 
+ 1.0383 \\cdot \\sbc{Z}^2 - 1.2943 \\cdot \\sbc{Z} + 0.837 \\right) = \\sbc
{beta01} \\NR)
tex.print(\\NC  \\NC \\beta \\NC = 25 \\cdot \\left[ \\left(0.1 - X 
\\right) 
\\cdot \\beta_{0.06} + \\left(X - 0.06 \\right) \\cdot \\beta_{0.1} \\right]= 
\\NR)
tex.print(\\NC  \\NC\\NC = 25 \\cdot \\left[ \\left(0.1 - 
\\sbd{X} 
\\right) \\cdot \\sbc{beta006} + \\left(\\sbd{X} - 0.06 \\right) \\cdot \\sbc
{beta01} \\right]=\\sbd{beta} \\NR)
elseif X==0.1 then
tex.print(\\NC  \\NC \\beta_{0.1} \\NC = N \\cdot \\left(-0.1833 
\\cdot Z^3 
+ 1.0383 \\cdot Z^2 - 1.2943 \\cdot Z + 0.837 \\right) = \\NR)
tex.print(\\NC  \\NC  \\NC = N \\cdot 
\\left(-0.1833 \\cdot \\sbc{Z}^3 
+ 1.0383 \\cdot \\sbc{Z}^2 - 1.2943 \\cdot \\sbc{Z} + 0.837 \\right) = \\sbc
{beta01} \\NR)
tex.print(\\NC  \\NC \\beta   \\NC =\\beta_{0.1}=\\sbc{beta01} 
\\NR)
elseif X0.1 and X0.2 then
tex.print(\\NC  \\NC \\beta_{0.1} \\NC = N \\cdot \\left(-0.1833 
\\cdot Z^3 
+ 1.0383 \\cdot Z^2 - 1.2943 \\cdot Z + 0.837 \\right) = \\NR)
tex.print(\\NC  \\NC   \\NC = N \\cdot 
\\left(-0.1833 \\cdot \\sbc{Z}^3 
+ 1.0383 \\cdot \\sbc{Z}^2 - 1.2943 \\cdot \\sbc{Z} + 0.837 \\right) = \\sbc
{beta01} \\NR)
tex.print(\\NC  \\NC \\beta_{0.2} \\NC = max \\left[ 0.95 \\cdot 
\\left(0.56 
- 1.94 \\cdot Y - 82.5 \\cdot Y^2 \\right); 0.5 \\right] \\NR)
tex.print(\\NC  \\NC  \\NC = max \\left[ 0.95 \\cdot 
\\left(0.56 
- 1.94 \\cdot \\sbd{Y} - 82.5 \\cdot \\sbd{Y}^2 \\right); 0.5 \\right] = \\sbd
{beta02} \\NR)
tex.print(\\NC  \\NC \\beta \\NC = 10 \\cdot \\left[ \\left(0.2 - X 
\\right) 
\\cdot \\beta_{0.1} + \\left(X - 0.1 \\right) \\cdot \\beta_{0.2} \\right]= 
\\NR)
tex.print(\\NC  \\NC\\NC = 10 \\cdot \\left[ \\left(0.2 - 
\\sbd{X} 
\\right) \\cdot \\sbc{beta01} + \\left(\\sbd{X} - 0.1 \\right) \\cdot \\sbc
{beta02} \\right]=\\sbd{beta} \\NR)
elseif X==0.2 then
tex.print(\\NC  \\NC \\beta_{0.2} \\NC = max \\left[ 0.95 \\cdot 
\\left(0.56 
- 1.94 \\cdot Y - 82.5 \\cdot Y^2 \\right); 0.5 \\right] \\NR)
tex.print(\\NC  \\NC  \\NC = max \\left[ 0.95 \\cdot 
\\left(0.56 
- 1.94 \\cdot \\sbd{Y} - 82.5 \\cdot \\sbd{Y}^2 \\right); 0.5 \\right] = \\sbd
{beta02} \\NR)
tex.print(\\NC  \\NC \\beta   \\NC =\\beta_{0.2}=\\sbd{beta02} 
\\NR)
end
\stopluacode
\stopalign
\stopformula
\setupformulas[align=middle]

I have already tried to insert split=yes in the options of the align 
environment without success.
I have read in Using \startalign and friends which is a document dated 2006  
that the splitting capability of \startalign is broken. Is it still so?

And by the way, is there a clever way to write a block of text under some 
conditions as shown in the example above other than tex.print(.) which 
forces to escape every command?
Thank you very much.
Bye



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