Hi Bart
On Thu, Dec 11, 2008 at 9:50 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
When I run the code below (via minimals), I get the following error, why?
enter loop
! Extra \else.
\@@plniterate ...\expandafter \@@plniterate \else
\fi
\myloop ...by 1 \ifnum \tempcnta #1\else \repeat
I
When I run the code below (via minimals), I get the following error, why?
enter loop
! Extra \else.
\@@plniterate ...\expandafter \@@plniterate \else
\fi
\myloop ...by 1 \ifnum \tempcnta #1\else \repeat
Zhichu Chen wrote:
Hi Bart
On Thu, Dec 11, 2008 at 9:50 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
When I run the code below (via minimals), I get the following error, why?
enter loop
! Extra \else.
\@@plniterate ...\expandafter \@@plniterate \else
\fi
\myloop ...by 1 \ifnum \tempcnta
On Thursday 11 December 2008 07:17:51 am Hans Hagen wrote:
Zhichu Chen wrote:
Hi Bart
On Thu, Dec 11, 2008 at 9:50 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
When I run the code below (via minimals), I get the following error,
why?
enter loop
! Extra \else.
\@@plniterate
Bart C. Wise wrote:
On Thursday 11 December 2008 07:17:51 am Hans Hagen wrote:
Zhichu Chen wrote:
Hi Bart
On Thu, Dec 11, 2008 at 9:50 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
When I run the code below (via minimals), I get the following error,
why?
enter loop
! Extra \else.
On Thursday 11 December 2008 07:29:15 am Zhichu Chen wrote:
Hi Bart,
On Thu, Dec 11, 2008 at 10:21 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
If I change the loop to be the following, I still get the same error:
\def\myloop#1{%
\tempcnta=\the\startcnt%
\loop
\advance \tempcnta
On Thu, 11 Dec 2008, Aditya Mahajan wrote:
On Thu, 11 Dec 2008, Bart C. Wise wrote:
When I run the code below (via minimals), I get the following error, why?
\newcount\startcnt
\newcount\tempcnta
\def\myloop#1{%
\message{enter}
\tempcnta=\the\startcnt%
\loop
\message{loop}
\advance
On Thursday 11 December 2008 08:28:40 am Zhichu Chen wrote:
Hi Bart,
On Thu, Dec 11, 2008 at 11:05 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
Chen,
Thanks. That makes sense now. However, when I take your code and run
it, it only goes through 1 iteration of the loop and exits. I'm
On Thu, 11 Dec 2008, Bart C. Wise wrote:
When I run the code below (via minimals), I get the following error, why?
\newcount\startcnt
\newcount\tempcnta
\def\myloop#1{%
\message{enter}
\tempcnta=\the\startcnt%
\loop
\message{loop}
\advance \tempcnta by 1
\ifnum\tempcnta#1\else
Am Thu, 11 Dec 2008 07:21:56 -0700 schrieb Bart C. Wise:
If I change the loop to be the following, I still get the same error:
\def\myloop#1{%
\tempcnta=\the\startcnt%
\loop
\advance \tempcnta by 1
\if\tempcnta=#1\else \repeat\fi
}
No, the \repeat take the place of the
On Thursday 11 December 2008 08:10:38 am Ulrike Fischer wrote:
Am Thu, 11 Dec 2008 07:21:56 -0700 schrieb Bart C. Wise:
If I change the loop to be the following, I still get the same error:
\def\myloop#1{%
\tempcnta=\the\startcnt%
\loop
\advance \tempcnta by 1
Hi Bart,
On Thu, Dec 11, 2008 at 11:05 PM, Bart C. Wise
[EMAIL PROTECTED] wrote:
Chen,
Thanks. That makes sense now. However, when I take your code and run it, it
only goes through 1 iteration of the loop and exits. I'm puzzled.
Bart
Really? 'cause when I run the following code
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