The following minimal example goes wrong:
\starttext
\startitemize[a]
\item sub a
\startitemize
\item sub a1
\item sub a2
\stopitemize
\item sub b
\stopitemize
\stoptext
The result is:
. sub a
- sub a1
- sub a2
a. sub b
Whereas:
\starttext
\startitemize[a]
On Mon, May 19, 2008 at 2:08 PM, Hans van der Meer [EMAIL PROTECTED] wrote:
The following minimal example goes wrong:
\starttext
\startitemize[a]
\item sub a
\startitemize
\item sub a1
\item sub a2
\stopitemize
\item sub b
\stopitemize
\stoptext
The result
Aditya,
Many thanks, that works beautifully.
Thanks again.
Richard
On Tue, 29 Apr 2008, [EMAIL PROTECTED] wrote:
Hello All,
I just tried the following on Context Live:
\starttext
\startitemize[n]
\item one
\item two
\startitemize
\item a
\item b
\stopitemize
Am 2008-04-29 um 17:49 schrieb Aditya Mahajan:
I just tried the following on Context Live:
\starttext
\startitemize[n]
\item one
\item two
\startitemize
\item a
\item b
\stopitemize
\item three
\stopitemize
\stoptext
and the first itemize starts at 0. Remove the
On Wed, 30 Apr 2008, Henning Hraban Ramm wrote:
Am 2008-04-29 um 17:49 schrieb Aditya Mahajan:
I just tried the following on Context Live:
\starttext
\startitemize[n]
\item one
\item two
\startitemize
\item a
\item b
\stopitemize
\item three
\stopitemize
\stoptext
Hello All,
I just tried the following on Context Live:
\starttext
\startitemize[n]
\item one
\item two
\startitemize
\item a
\item b
\stopitemize
\item three
\stopitemize
\stoptext
and the first itemize starts at 0. Remove the inner itemize and it starts
at 1.
Is
On Tue, 29 Apr 2008, [EMAIL PROTECTED] wrote:
Hello All,
I just tried the following on Context Live:
\starttext
\startitemize[n]
\item one
\item two
\startitemize
\item a
\item b
\stopitemize
\item three
\stopitemize
\stoptext
and the first itemize starts at 0.