When I have a Lua function with 2 arguments:
\startluacode
function f(a,b)
...
\stopluacode
called through:
\def\callf#1#2{\ctxlua{f(#1,#2)}}
and do this actually with one argument:
\callf{one}
then I find that the absent argument b in f(a,b) is
On 30-3-2010 19:45, Hans van der Meer wrote:
When I have a Lua function with 2 arguments:
\startluacode
function f(a,b)
...
\stopluacode
called through:
\def\callf#1#2{\ctxlua{f(#1,#2)}}
and do this actually with one argument:
\callf{one}
so, #1 will be one and #2 will be the next token
On Tue, Mar 30 2010, Hans van der Meer wrote:
called through:
\def\callf#1#2{\ctxlua{f(#1,#2)}}
and do this actually with one argument:
\callf{one}
then I find that the absent argument b in f(a,b) is not nil but a string of
length 1.
Hello Hans,
You want probably something
