Re: [Numpy-discussion] (no subject)

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[Numpy-discussion] PHxoeARMA

2006-09-16 Thread Sib Ridenhour
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[Numpy-discussion] 1.0b5 Installation on OS X

2006-09-16 Thread David Andrews
Hi, I'm unable to install the 1.0b5 release from the .mpkg on OS X - when it comes to the two checkboxes to select the platlib and the scripts, both are greyed out. The installer then claims 'Cannot continue: Nothing to install'. Any suggestions? Cheers, Dave -

[Numpy-discussion] A Job offer

2006-09-16 Thread Casandra
Dear Friend, Taken into account the expansion of a field of activity of our firm, which is located in Europe and engaged in modeling and fashion industry in the world markets. We require Project Manager. The job is of a partial employment, which means that you will not spend a lot of energy and

[Numpy-discussion] concatenation changes dtype

2006-09-16 Thread Martin Wiechert
Hi list, Apparently r_[x,x] does not necessarily have the same dtype as x: >>> from numpy import * >>> dt = dtype ([('a', 'b'), ('f4', 'i4')]) >>> x = zeros ((1,), dt) >>> x.dtype dtype([('a', '|i1'), ('f4', '>> r_[x,x].dtype dtype('object') >>> >>> import numpy >>> numpy.version.version '1.0rc1.

Re: [Numpy-discussion] concatenation changes dtype

2006-09-16 Thread Travis Oliphant
Martin Wiechert wrote: > Hi list, > > Apparently r_[x,x] does not necessarily have the same dtype as x: > > from numpy import * dt = dtype ([('a', 'b'), ('f4', 'i4')]) x = zeros ((1,), dt) x.dtype > dtype([('a', '|i1'), ('f4', ' r_[x,x].dtype

Re: [Numpy-discussion] concatenation changes dtype

2006-09-16 Thread Travis Oliphant
Martin Wiechert wrote: > Hi list, > > Apparently r_[x,x] does not necessarily have the same dtype as x: > > from numpy import * dt = dtype ([('a', 'b'), ('f4', 'i4')]) x = zeros ((1,), dt) x.dtype > dtype([('a', '|i1'), ('f4', ' Did you mean to make a data-t

Re: [Numpy-discussion] concatenation changes dtype

2006-09-16 Thread Martin Wiechert
On Sunday 17 September 2006 00:36, Travis Oliphant wrote: > Martin Wiechert wrote: > > Hi list, > > > > Apparently r_[x,x] does not necessarily have the same dtype as x: > from numpy import * > dt = dtype ([('a', 'b'), ('f4', 'i4')]) > x = zeros ((1,), dt) > x.dtype > > > > dtyp