Hi,
I wondered if there was a way of returning another error code than 0 when
executing the test suite so that a parent process can immediately know if
all the tests passed or not.
The numpy buildbot seems to have the same behaviour BTW.
I don't know if it is possible, but it would be great.
Greetings,
I struggling with the numpy C-API (version 1.0.3).
Now I have obscurities concerning the reference counter of builtin
descriptor objects. In some situation, when running my own code, the
reference counter fall to zero an I get warning messages. In some other
samples the reference
Hi,
The latest release notes of pyOpenGL (Feb 15, 2007) say that Numarray
support [was] reenabled.
The current version is 3.0.0a6.
Does anyone here know the status of the new (ctypes based) pyOpenGL ?
How is the binding to (modern) numpy ?
I'm especially interested in fast memory access. So far
There may be multiple nan-s, but what Chris did is simply create one
with the same nan's
a = N.array((1,2,3,N.nan))
b = N.array((1,2,3,N.nan))
I think these should be the same.
Can anybody give me a good reason why they shouldn't, because it could
confuse a lot of people?
Thanks, Mark
ps. I
2007/8/24, mark [EMAIL PROTECTED]:
There may be multiple nan-s, but what Chris did is simply create one
with the same nan's
a = N.array((1,2,3,N.nan))
b = N.array((1,2,3,N.nan))
I think these should be the same.
Can anybody give me a good reason why they shouldn't, because it could
On Fri, Aug 24, 2007 at 05:25:43PM +0200, Matthieu Brucher wrote:
It's the IEEE norm for flotting point numbers. You can have sevaral
different NaN, although in this case, they are the same kind.
Even if they are the same kind, the norm tells that NaN != NaN.
Someone mentioned using masked
On 8/25/07, Matthieu Brucher [EMAIL PROTECTED] wrote:
2007/8/24, mark [EMAIL PROTECTED]:
There may be multiple nan-s, but what Chris did is simply create one
with the same nan's
a = N.array((1,2,3,N.nan))
b = N.array((1,2,3,N.nan))
I think these should be the same.
Can anybody
Matthieu Brucher wrote:
2007/8/24, mark [EMAIL PROTECTED] mailto:[EMAIL PROTECTED]:
There may be multiple nan-s, but what Chris did is simply create one
with the same nan's
a = N.array((1,2,3,N.nan))
b = N.array((1,2,3,N.nan))
I think these should be the same.
On 8/24/07, Christopher Barker [EMAIL PROTECTED] wrote:
[SNIP]
You can have several different NaN,
You can? I thought NaN was defined by IEEE 754 as a particular bit
pattern (one for each precision, anyway).
There's more than one way to spell NaN in binary and they tend to mean
different
What is meant by multiple nan-s?
DG
mark wrote:
There may be multiple nan-s, but what Chris did is simply create one
with the same nan's
a = N.array((1,2,3,N.nan))
b = N.array((1,2,3,N.nan))
I think these should be the same.
Can anybody give me a good reason why they
Never mind. (Posted that before finishing the thread, sorry).
DG
David Goldsmith wrote:
What is meant by multiple nan-s?
DG
mark wrote:
There may be multiple nan-s, but what Chris did is simply create one
with the same nan's
a = N.array((1,2,3,N.nan))
b =
On 8/24/07, Timothy Hochberg [EMAIL PROTECTED] wrote:
On 8/24/07, Christopher Barker [EMAIL PROTECTED] wrote:
[SNIP]
You can have several different NaN,
You can? I thought NaN was defined by IEEE 754 as a particular bit
pattern (one for each precision, anyway).
There's more than
Timothy Hochberg wrote:
in principle it's not safe to rely on NaNs being bitwise equal.
Thanks Tim, I always learn a lot on this list.
Anyway, I think my suggestion of binary equal wasn't really what I
want. What I want is essentially a NaN-safe comparison, much like the
NaN-safe functions
All,
Using the maskedarray package:
import maskedarray as ma
x = numpy.array([1,numpy.nan,3])
y = numpy.array([1,numpy.nan,3])
ma.allclose(ma.array(x,mask=numpy.isnan(x)),ma.array(y,mask=numpy.isnan(y)) )
True
or even simpler:
maskedarray.testutils.assert_equal(x,y)
Sebastian Haase wrote:
Hi,
The latest release notes of pyOpenGL (Feb 15, 2007) say that Numarray
support [was] reenabled.
The current version is 3.0.0a6.
Does anyone here know the status of the new (ctypes based) pyOpenGL ?
How is the binding to (modern) numpy ?
numpy is the primary array
I have a simple question (I assume), but I can't quite get a handle on the
answer. I have a dict with each member a list having a long (5M
elements). I would like to convert that into a numpy recarray. So far, my
only thought is to loop over the length of the lists and convert to a list
of
On 8/24/07, Sean Davis [EMAIL PROTECTED] wrote:
I have a simple question (I assume), but I can't quite get a handle on the
answer. I have a dict with each member a list having a long (5M
elements). I would like to convert that into a numpy recarray. So far, my
only thought is to loop over
I know thanks have already been offered,
but I hope one more on the list will be acceptable.
I start classes next week, in Economics.
It is easy to discourage some of my students,
if the getting started part of new software is rough.
The new compatible NumPy and SciPy binaries are VERY HELPFUL!!!
I helped a coulpe of my students install on Vista. It was enough to
right click on the exe and choose Run as Administrator. A pop-up
window then comes up asking you if you trust the file or something and
you have to chose an option that is something like, yes, let it
proceed.
On 8/24/07, Alan
Try itertools.izipping the lists and then use numpy.fromiter.
On 8/24/07, Sean Davis [EMAIL PROTECTED] wrote:
On 8/24/07, Sean Davis [EMAIL PROTECTED] wrote:
I have a simple question (I assume), but I can't quite get a handle on the
answer. I have a dict with each member a list having a
All,
As you might be aware, there are currently two concurrent implementations of
masked arrays in numpy:
* numpy.ma is the official implementation, but it is unclear whether it is
still actively maintained.
* maskedarray is the alternative I've been developing initially for my own
purpose
On Fri, 24 Aug 2007, Ryan Krauss apparently wrote:
I helped a couple of my students install on Vista. It was
enough to right click on the exe and choose Run as
Administrator. A pop-up window then comes up asking you
if you trust the file or something and you have to chose
an option that
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