Hello,
I want to divide an n x n (2-dimension) numpy array matrix A by a n
(1-dimension) array d as follows:
Take n = 2.
Let A= 2 3
1 10
and let d = [ 3 2 ]
Then i would like to have A/d = 2/3 3/3
1/2 10/2
This is to avoid loops to
Hello,
I want to divide an n x n (2-dimension) numpy array matrix A by a n
(1-dimension) array d as follows:
Take n = 2.
Let A= 2 3
1 10
and let d = [ 3 2 ]
Then i would like to have A/d = 2/3 3/3
1/2 10/2
This is to avoid loops to
On Fri, Mar 12, 2010 at 12:52, gerardo.berbeglia gberbeg...@gmail.com wrote:
Hello,
I want to divide an n x n (2-dimension) numpy array matrix A by a n
(1-dimension) array d as follows:
Take n = 2.
Let A= 2 3
1 10
and let d = [ 3 2 ]
Then i would like to have A/d = 2/3 3/3
import numpy
A = numpy.asarray([[2, 3], [1, 10]])
print A
[[ 2 3]
[ 1 10]]
d = numpy.asarray([3, 2])
print d
[3 2]
print (A.T * (1.0 / d)).T
[[ 0.6667 1.]
[ 0.5 5.]]
- or -
d = numpy.asarray([3.0, 2.0])
print d
[ 3. 2.]
print (A.T / d).T
[[ 0.6667
On 12 March 2010 13:54, gerardo.berbeglia gberbeg...@gmail.com wrote:
Hello,
I want to divide an n x n (2-dimension) numpy array matrix A by a n
(1-dimension) array d as follows:
Look up broadcasting in the numpy docs. The short version is this:
operations like division act elementwise on
