Good morning all
I have been using the financial functions for a while now, and the npv
function has always bothered me. Indeed neither the documentation nor the
implementation seem to be correct, and actually are not congruent with each
other either.
As stated in the bug report https://github.co
On Wed, May 22, 2013 at 11:15 AM, eat wrote:
> FWIW, apparently bug related to dtype of np.eye(.)
sort of -- the issue shows up when assigning a float64 array (default
for eye()) to a rank-0 array with a custom dtype that has a single
object filed that is an arraynumpy should do the right th
Thanks, I filed a new issue on the bug tracker.
Nicolas
On May 22, 2013, at 8:15 PM, eat wrote:
> Hi,
>
> FWIW, apparently bug related to dtype of np.eye(.)
>
>
> On Wed, May 22, 2013 at 8:07 PM, Nicolas Rougier
> wrote:
>
>
> Hi all,
>
> I got a weird output from the following scr
Hi,
FWIW, apparently bug related to dtype of np.eye(.)
On Wed, May 22, 2013 at 8:07 PM, Nicolas Rougier
wrote:
>
>
> Hi all,
>
> I got a weird output from the following script:
>
> import numpy as np
>
> U = np.zeros(1, dtype=[('x', np.float32, (4,4))])
>
> U[0] = np.eye(4)
> print U[0]
> # out
On Wed, May 22, 2013 at 10:07 AM, Nicolas Rougier
> U = np.zeros(1, dtype=[('x', np.float32, (4,4))])
>
> U[0] = np.eye(4)
> print U[0]
> # output: ([[0.0, 1.875, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0,
> 1.875], [0.0, 0.0, 0.0, 0.0]],)
I get the same thing. Note:
In [86]: U[0].shape
O
Hi all,
I got a weird output from the following script:
import numpy as np
U = np.zeros(1, dtype=[('x', np.float32, (4,4))])
U[0] = np.eye(4)
print U[0]
# output: ([[0.0, 1.875, 0.0, 0.0], [0.0, 0.0, 0.0, 0.0], [0.0, 0.0, 0.0,
1.875], [0.0, 0.0, 0.0, 0.0]],)
U[0] = np.eye(4, dtype=np.float
