Sorry typo :
a = np.ones(30)
idx = np.array([2,3,2]) # there is a duplicate index of 2
a[idx] += 2
On Fri, Feb 22, 2013 at 8:35 PM, santhu kumar wrote:
> Hi all,
>
> I dont want to run a loop for this but it should be possible using numpy
> "smart" ways.
>
> a =
Hi all,
I dont want to run a loop for this but it should be possible using numpy
"smart" ways.
a = np.ones(30)
idx = np.array([2,3,2]) # there is a duplicate index of 2
a += 2
>>>a
array([ 1., 1., 3., 3., 1., 1., 1., 1., 1., 1., 1., 1., 1.,
1., 1., 1., 1., 1., 1., 1.,
Hello all,
I was able to successfully embed python code into C code. The basic
skeleton is something like this :
In C code :
PyObject *pName, *pModule, *pFunc,*pArgs,*pReturn;
PyArrayObject *cusForce;
Py_Initialize();
import_array(); // required while using numpy arrays in C
// Call some
Please ignore the previous message. I have done some testing and found it
to be running on a client node instead of the master node.
The problem might be because node2, does not have numpy installed. Thanks.
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Hello,
I have embedded python/numpy scripts in an application that runs in
parallel.
But the python code is always invoked on the master node.
So it could be assumed that at some point, there could be multiple
instances of script being invoked and run.
I have commented out import numpy part to se
Hello all,
I am trying to optimise a code and want your suggestions.
A : - NX3 matrix (coordinates of N points)
After performing pairwise distance computations(called pdist) between these
points, depending upon a condition that the distance is in, I would perform
further computations.
Most of the
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Message: 1
> Date: Fri, 3 Feb 2012 09:10:28 -0500
> From: josef.p...@gmail.com
> Subject: Re: [Numpy-discussion] Trick for fast
> To: Discussion of Numerical Python
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> On Fri, Feb 3, 2012 at 8:44 AM
Hello all,
I have tried to optimize most of my code but this ones seems to be the
major bottleneck as it gets called many times. I have run out of ideas to
make it more faster, can somebody please help me here.
x = nX3 vector.
mass = nX1 vector
inert = zeros((3,3))
for i in range(n):
ri = x
x27; to
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&g
Hello,
I have a 380X5 matrix and when I am calculating pseudo-inverse of the matrix
using pinv(numpy.linalg) I get the following error message:
raise LinAlgError, 'SVD did not converge'
numpy.linalg.linalg.LinAlgError: SVD did not converge
I have looked in the list that it is a recurring issue b
Hello All,
I am trying to extend a piece of matlab code into numpy.
And I am stuck at converting, ( x is a nX3 matrix)
Matlab :
dim = size(x,1) % would be n
nx = x(:,:,ones(1,dim)) % would be nX3Xn matrix ..
Now the same in Numpy seems to be tricky to me .. Can somebody help me in
writing this p
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> Message: 2
> Date: Thu, 17 Mar 2011 23:19:42 +0100
> From: Matthieu Brucher
> Subject: Re: [Numpy-disc
Hello all,
I am new to Numpy. I used to program before in matlab and am getting used to
Numpy.
I have a array like:
res
array([[ 33.35053669, 49.4615004 , 44.27631299, 1., 2.
],
[ 32.84263059, 50.24752036, 43.92291659, 1., 0.
],
[ 33.68999668, 48.9055467
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