Re: [Numpy-discussion] Advanced indexing question - subset of data cube as a 2D array.

2008-10-29 Thread Adam Ginsburg
In [85]: bi = (f.bolo_indices[np.newaxis,:]+ ones([7751,1])).astype('int') In [86]: whc = (whscan[:,np.newaxis] + ones([1,107])).astype('int') In [87]: array2d[whc,bi] = temp2d I thought this had worked, but the values didn't seem to be going to the right places when I re-examined them.

Re: [Numpy-discussion] Advanced indexing question - subset of data cube as a 2D array.

2008-10-29 Thread Ravi
On Wednesday 29 October 2008 01:44:06 Adam wrote: In [62]: temp2d = reshape(array3d,[23*337,107]) In [63]: temp2d2 = zeros([23*337,144]) In [64]: temp2d2[:,f.bolo_indices] = temp2d In [65]: array2d[whscan,:] = temp2d2 This works, but it feels wrong to me: I think there should be a way to

[Numpy-discussion] Advanced indexing question - subset of data cube as a 2D array.

2008-10-28 Thread Adam
Hi numpy group, I have a problem I know there is an elegant solution to, but I can't wrap my head around the right way to do the indexing. The problem: I have a 2D array that has been chopped up into 3 dimensions - it was [ time X detectors ], it is now [ scans X time X detectors ]. During