From: Anne Archibald
On 6 April 2010 15:42, Ken Basye wrote:
> Folks,
> I hope this is a simple question. When I created a ufunc with
> np.frompyfunc(), I got an error when I called the result with an 'out'
> argument:
In fact, ordinary ufuncs do not accept names for their arguments. T
On 6 April 2010 15:42, Ken Basye wrote:
> Folks,
> I hope this is a simple question. When I created a ufunc with
> np.frompyfunc(), I got an error when I called the result with an 'out'
> argument:
In fact, ordinary ufuncs do not accept names for their arguments. This
is annoying, but fixing it
Folks,
I hope this is a simple question. When I created a ufunc with
np.frompyfunc(), I got an error when I called the result with an 'out'
argument:
>>> def foo(x): return x * x + 1
>>> ufoo = np.frompyfunc(foo, 1, 1)
>>> arr = np.arange(9).reshape(3,3)
>>> ufoo(arr, out=arr)
Traceback (
