On Mon, Feb 9, 2009 at 12:32 AM, Xiaoyu Chu beryl@gmail.com wrote:
Hey all,
I am currently working on a large matrix, and I already have a
specific eigen value that I want to use in order to find out its
corresponding eigen vector. Is there an easy way to do so?
I have tried
Hey all,
I am currently working on a large matrix, and I already have a
specific eigen value that I want to use in order to find out its
corresponding eigen vector. Is there an easy way to do so?
I have tried with linalg.solve(a, b), where I put a as the
Matrix A - eigen value* unit
I have tried with linalg.solve(a, b), where I put a as the
Matrix A - eigen value* unit matrix, and b as the zero matrix. But the
solution returned is a zero matrix, which I really find disappointing.
So if you're trying to solve (A - \lambda I) x = b, try appending an
extra row to your