19/08/10 @ 18:03 (-0600), thus spake Charles R Harris:
2010/8/19 Ernest Adrogué eadro...@gmx.net
Hi,
I was trying to use lexsort with an array of
datetime.date objects, but it doesn't seem to work.
In [86]: date = np.array([datetime.date(2000, 9, 17),
datetime.date(2000, 10, 1),
Hi,
I was trying to use lexsort with an array of
datetime.date objects, but it doesn't seem to work.
In [86]: date = np.array([datetime.date(2000, 9, 17),
datetime.date(2000, 10, 1),
datetime.date(2000, 10, 22),
datetime.date(2000, 11, 1)])
In [90]: date
Out[90]: array([2000-09-17,
2010/8/19 Ernest Adrogué eadro...@gmx.net
Hi,
I was trying to use lexsort with an array of
datetime.date objects, but it doesn't seem to work.
In [86]: date = np.array([datetime.date(2000, 9, 17),
datetime.date(2000, 10, 1),
datetime.date(2000, 10, 22),
datetime.date(2000, 11, 1)])
a = numpy.array([[1,2,6], [2,2,8], [2,1,7],[1,1,5]])
a
array([[1, 2, 6],
[2, 2, 8],
[2, 1, 7],
[1, 1, 5]])
indices = numpy.lexsort(a.T)
a.T.take(indices,axis=-1).T
array([[1, 1, 5],
[1, 2, 6],
[2, 1, 7],
[2, 2, 8]])
The above does what I want,
2008/5/6 Eleanor [EMAIL PROTECTED]:
a = numpy.array([[1,2,6], [2,2,8], [2,1,7],[1,1,5]])
a
array([[1, 2, 6],
[2, 2, 8],
[2, 1, 7],
[1, 1, 5]])
indices = numpy.lexsort(a.T)
a.T.take(indices,axis=-1).T
array([[1, 1, 5],
[1, 2, 6],
[2, 1, 7],
Anne Archibald peridot.faceted at gmail.com writes:
It appears that lexsort is broken in several ways, and its docstring
is misleading.
First of all, this code is not doing quite what you describe. The
primary key here is the [5,6,7,8] column, followed by the middle and
then by the
