Alternatively, to solve A x = b you could do
import numpy
import numpy.linalg
B = numpy.dot(A.T, A)
c = numpy.dot(A.T, b)
x = numpy.linalg(B,c)
This is not the most efficient way to do it but at least you know
exactly what's going on in your code.
On Sun, May 17, 2009 at 7:21 PM,
2009/5/18 Sebastian Walter sebastian.wal...@gmail.com:
B = numpy.dot(A.T, A)
This multiplication should be avoided whenever possible -- you are
effectively squaring your condition number.
In the case where you have more rows than columns, use least squares.
For square matrices use solve. For
2009/5/18 Stéfan van der Walt ste...@sun.ac.za:
2009/5/18 Sebastian Walter sebastian.wal...@gmail.com:
B = numpy.dot(A.T, A)
This multiplication should be avoided whenever possible -- you are
effectively squaring your condition number.
Indeed.
In the case where you have more rows than
2009/5/18 Stéfan van der Walt ste...@sun.ac.za
2009/5/18 Sebastian Walter sebastian.wal...@gmail.com:
B = numpy.dot(A.T, A)
This multiplication should be avoided whenever possible -- you are
effectively squaring your condition number.
Although the condition number doesn't mean much unless
On Mon, May 18, 2009 at 10:55 AM, Charles R Harris
charlesr.har...@gmail.com wrote:
2009/5/18 Stéfan van der Walt ste...@sun.ac.za
2009/5/18 Sebastian Walter sebastian.wal...@gmail.com:
B = numpy.dot(A.T, A)
This multiplication should be avoided whenever possible -- you are
effectively
On Mon, May 18, 2009 at 9:35 AM, josef.p...@gmail.com wrote:
On Mon, May 18, 2009 at 10:55 AM, Charles R Harris
charlesr.har...@gmail.com wrote:
2009/5/18 Stéfan van der Walt ste...@sun.ac.za
2009/5/18 Sebastian Walter sebastian.wal...@gmail.com:
B = numpy.dot(A.T, A)
This
Right the dimensions I gave were wrong.
What do I need to do for m=n (more rows than columns)? Can I use the
same function?
When I run the script written by Nils (thanks!) I get:
from numpy.random import rand, seed
ImportError: No module named random
But importing numpy works ok. What do I
On Sun, May 17, 2009 at 12:14 PM, Quilby qui...@gmail.com wrote:
Right the dimensions I gave were wrong.
What do I need to do for m=n (more rows than columns)? Can I use the
same function?
When I run the script written by Nils (thanks!) I get:
from numpy.random import rand, seed
Hi-
This is what I need to do-
I have this equation-
Ax = y
Where A is a rational m*n matrix (m=n), and x and y are vectors of
the right size. I know A and y, I don't know what x is equal to. I
also know that there is no x where Ax equals exactly y. I want to find
the vector x' such that Ax' is
On Sat, 16 May 2009 16:01:00 +0300
Quilby qui...@gmail.com wrote:
Hi-
This is what I need to do-
I have this equation-
Ax = y
Where A is a rational m*n matrix (m=n), and x and y are
vectors of
the right size. I know A and y, I don't know what x is
equal to. I
also know that there
On Sat, May 16, 2009 at 9:01 AM, Quilby qui...@gmail.com wrote:
Hi-
This is what I need to do-
I have this equation-
Ax = y
Where A is a rational m*n matrix (m=n), and x and y are vectors of
the right size. I know A and y, I don't know what x is equal to. I
also know that there is no x
On 5/16/2009 9:01 AM Quilby apparently wrote:
Ax = y
Where A is a rational m*n matrix (m=n), and x and y are vectors of
the right size. I know A and y, I don't know what x is equal to. I
also know that there is no x where Ax equals exactly y.
If m=n, that can only be true if there are not
m
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