thanks Sturl, your second code works well although I had to divide the
vector elements through 128 to get just the binaries
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If I want to generate a string of random bits with equal probability I run
random.randint(0,2,size).
What if I want a specific proportion of bits? In other words, each bit is 1
with probability p1/2 and 0 with probability q=1-p?
thanks
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Hi,
On Tue, Mar 29, 2011 at 12:00 PM, Alex Ter-Sarkissov ater1...@gmail.comwrote:
If I want to generate a string of random bits with equal probability I run
random.randint(0,2,size).
What if I want a specific proportion of bits? In other words, each bit is 1
with probability p1/2 and 0
On Tue, Mar 29, 2011 at 1:29 PM, eat e.antero.ta...@gmail.com wrote:
Hi,
On Tue, Mar 29, 2011 at 12:00 PM, Alex Ter-Sarkissov
ater1...@gmail.comwrote:
If I want to generate a string of random bits with equal probability I run
random.randint(0,2,size).
What if I want a specific
Den 29.03.2011 11:00, skrev Alex Ter-Sarkissov:
If I want to generate a string of random bits with equal probability I
run
random.randint(0,2,size).
What if I want a specific proportion of bits? In other words, each bit
is 1 with probability p1/2 and 0 with probability q=1-p?
Does this
Den 29.03.2011 14:56, skrev Sturla Molden:
import numpy as np
def randombits(n, p):
b = (np.random.rand(n*8).reshape((n,8)) p).astype(int)
return (b range(8)).sum(axis=1).astype(np.uint8)
n is the number of bytes. If you prefer to count in bits:
def randombits(n, p):
On Tue, Mar 29, 2011 at 5:00 AM, Alex Ter-Sarkissov ater1...@gmail.com wrote:
If I want to generate a string of random bits with equal probability I run
random.randint(0,2,size).
What if I want a specific proportion of bits? In other words, each bit is 1
with probability p1/2 and 0 with
Den 29.03.2011 15:46, skrev Daniel Lepage:
x = (np.random.random(size) p)
This will not work. A boolean array is not compactly stored, but an
array of bytes. Only the first bit 0 is 1 with probability p, bits 1 to
7 bits are 1 with probability 0. We thus have to do this 8 times for
each
Den 29.03.2011 16:49, skrev Sturla Molden:
Only the first bit 0 is 1 with probability p, bits 1 to 7 bits are 1
with probability 0.
That should read:
Only bit 0 is 1 with probability p, bits 1 to 7 are 1 with probability 0.
Sorry :)
Sturla
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On Tue, Mar 29, 2011 at 09:49, Sturla Molden stu...@molden.no wrote:
Den 29.03.2011 15:46, skrev Daniel Lepage:
x = (np.random.random(size) p)
This will not work. A boolean array is not compactly stored, but an
array of bytes. Only the first bit 0 is 1 with probability p, bits 1 to
7 bits
Den 29.03.2011 16:49, skrev Sturla Molden:
This will not work. A boolean array is not compactly stored, but an
array of bytes. Only the first bit 0 is 1 with probability p, bits 1 to
7 bits are 1 with probability 0. We thus have to do this 8 times for
each byte, shift left by range(8), and
On Tue, Mar 29, 2011 at 11:59 AM, Sturla Molden stu...@molden.no wrote:
Den 29.03.2011 16:49, skrev Sturla Molden:
This will not work. A boolean array is not compactly stored, but an
array of bytes. Only the first bit 0 is 1 with probability p, bits 1 to
7 bits are 1 with probability 0.
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