Hello list,
I compute the index of the last term in an array that I need and call the
index n.
I can then call the array b as
b[:-n]
If I need all terms in the array, the logical syntax would be:
b[:-0]
but that doesn't work. Any reason why that has not been implemented? Any
elegant
I'm sure there is a better solution:
In [1]: x = numpy.array([i for i in range(10)])
In [2]: foo = lambda n: -n if n!=0 else None
:
In [3]: x[:foo(1)]
Out[3]: array([0, 1, 2, 3, 4, 5, 6, 7, 8])
In [4]: x[:foo(0)]
Out[4]: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
On Wed, Aug 19, 2009
The problem is that n is integer and integer do not have different
representations for 0 and -0 (while floats do).
Therefore it is impossible to disambiguate the following two case scenarios:
b[:n] # take the first n
b[:-n] # take all but the last n
when n ==0.
One possible solution (you
On Aug 19, 2009, at 7:25 AM, Mark Bakker wrote:
I compute the index of the last term in an array that I need and
call the index n.
I can then call the array b as
b[:-n]
If I need all terms in the array, the logical syntax would be:
b[:-0]
but that doesn't work. Any reason why that
Another solution (elegant?? readable??) :
x[slice(-n or None)] # with n == 0, 1, ...
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In [45]: x[: -0 or None]
Out[45]: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
In [46]: x[: -1 or None]
Out[46]: array([0, 1, 2, 3, 4, 5, 6, 7, 8])
works fine without slice()
On Wed, Aug 19, 2009 at 2:54 PM, Citi, Lucalc...@essex.ac.uk wrote:
Another solution (elegant?? readable??) :
x[slice(-n or
The winner so far:
x[: -n or None]
works fine when n = 0, relatively elegant, even pretty slick I think.
And I expect it to be quick.
Thanks for all the replys,
Mark
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Use N = len(b) and then b[:N-n]
-Travis
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Travis Oliphant
Enthought, Inc.
1-512-536-1057
http://www.enthought.com
On Aug 19, 2009, at 7:25 AM, Mark Bakker mark...@gmail.com wrote:
Hello list,
I compute the index of the last term in an array that I need and
call the
On Wed, Aug 19, 2009 at 5:50 AM, Neil Martinsen-Burrelln...@wartburg.edu
wrote:
On Aug 19, 2009, at 7:25 AM, Mark Bakker wrote:
I compute the index of the last term in an array that I need and
call the index n.
I can then call the array b as
b[:-n]
If I need all terms in the array, the
