2009/4/20 Wes McKinney wesmck...@gmail.com:
I assume that, because NaN != NaN, even though both have the same hash value
(hash(NaN) == -32768), that Python treats any NaN double as a distinct key
in a dictionary.
In [76]: a = np.repeat(nan, 10)
In [77]: d = {}
In [78]: for i, v in
josef.p...@gmail.com wrote:
2009/4/20 Wes McKinney wesmck...@gmail.com:
I assume that, because NaN != NaN, even though both have the same hash value
(hash(NaN) == -32768), that Python treats any NaN double as a distinct key
in a dictionary.
In [76]: a = np.repeat(nan, 10)
In [77]: d =
On Mon, Apr 20, 2009 at 11:42 PM, Wes McKinney wesmck...@gmail.com wrote:
I assume that, because NaN != NaN, even though both have the same hash value
(hash(NaN) == -32768), that Python treats any NaN double as a distinct key
in a dictionary.
I think that strictly speaking, nan should not be
