I want to accumulate elements of a vector (x) to an array (f) based on
an index list (ind).
For example:
x=[1,2,3,4,5,6]
ind=[1,3,9,3,4,1]
f=np.zeros(10)
What I want would be produced by the loop
for i=range(6):
f[ind[i]]=f[ind[i]]+x[i]
The answer is f=array([ 0., 7., 0., 6., 5.,
On Tue, Feb 19, 2013 at 10:00 AM, Tony Ladd tl...@che.ufl.edu wrote:
I want to accumulate elements of a vector (x) to an array (f) based on
an index list (ind).
For example:
x=[1,2,3,4,5,6]
ind=[1,3,9,3,4,1]
f=np.zeros(10)
What I want would be produced by the loop
for i=range(6):
On Tue, 2013-02-19 at 10:00 -0500, Tony Ladd wrote:
I want to accumulate elements of a vector (x) to an array (f) based on
an index list (ind).
For example:
x=[1,2,3,4,5,6]
ind=[1,3,9,3,4,1]
f=np.zeros(10)
What I want would be produced by the loop
for i=range(6):
x=[1,2,3,4,5,6]
ind=[1,3,9,3,4,1]
f=np.zeros(10)
np.bincount(ind,x)
hth,
Alan Isaac
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Alan
Thanks - I felt sure there had to be an easy idea.
Best
Tony
On 02/19/2013 10:17 AM, Alan G Isaac wrote:
x=[1,2,3,4,5,6]
ind=[1,3,9,3,4,1]
f=np.zeros(10)
np.bincount(ind,x)
hth,
Alan Isaac
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Thanks to all for a very quick response. np.bincount does what I need.
Tony
On 02/19/2013 10:04 AM, Benjamin Root wrote:
On Tue, Feb 19, 2013 at 10:00 AM, Tony Ladd tl...@che.ufl.edu
mailto:tl...@che.ufl.edu wrote:
I want to accumulate elements of a vector (x) to an array (f) based on
Dear Tony,
I would suggest to look at this post already mentioned by Benjamin .
maybe it fits with your needs!
http://numpy-discussion.10968.n7.nabble.com/Pre-allocate-array-td4870.html
Cheers,
Eraldo
On Tue, Feb 19, 2013 at 4:24 PM, Tony Ladd tl...@che.ufl.edu wrote:
Thanks to all for
