On Mon, 2013-04-15 at 13:36 -0600, Charles R Harris wrote:
On Mon, Apr 15, 2013 at 1:27 PM, Sebastian Berg
sebast...@sipsolutions.net wrote:
On Mon, 2013-04-15 at 11:16 -0600, Charles R Harris wrote:
On Mon, Apr 15, 2013 at 10:29 AM, Sebastian Berg
On Mon, Apr 15, 2013 at 5:29 PM, Sebastian Berg
sebast...@sipsolutions.net wrote:
Hey,
the MapIter API has only been made public in master right? So it is no
problem at all to change at least the mapiter struct, right?
I got annoyed at all those special cases that make things difficult to
I'm trying to do something that at first glance I think should be simple
but I can't quite figure out how to do it. The problem is as follows:
I have a 3D grid Values[Nx, Ny, Nz]
I want to slice Values at a 2D surface in the Z dimension specified by
Z_index[Nx, Ny] and return a 2D slice[Nx,
As one lurker to another, thanks for calling it out.
Over-argumentative, and personality centric threads like these have
actually led me to distance myself from the numpy community. I do not know
how common it is now because I do not follow it closely anymore. It used to
be quite common at one
I am curious if others have noticed an issue with datetime64 at the
beginning of 1970. First:
In [144]: (np.datetime64('1970-01-01') - np.datetime64('1969-12-31'))
Out[144]: numpy.timedelta64(1,'D')
OK this look fine, they are one day apart. But look at this:
In [145]:
On Tue, Apr 16, 2013 at 4:55 PM, Bob Nnamtrop bob.nnamt...@gmail.com wrote:
I am curious if others have noticed an issue with datetime64 at the
beginning of 1970. First:
In [144]: (np.datetime64('1970-01-01') - np.datetime64('1969-12-31'))
Out[144]: numpy.timedelta64(1,'D')
OK this look
On Tue, Apr 16, 2013 at 7:45 PM, Ondřej Čertík ondrej.cer...@gmail.comwrote:
On Tue, Apr 16, 2013 at 4:55 PM, Bob Nnamtrop bob.nnamt...@gmail.com
wrote:
I am curious if others have noticed an issue with datetime64 at the
beginning of 1970. First:
In [144]: (np.datetime64('1970-01-01') -
The problem does not appear to exist on Linux with numpy version 1.6.2.
In [1]: import numpy as np
In [2]: np.datetime64('1970-01-01') - np.datetime64('1969-12-31')
Out[2]: 1 day, 0:00:00
In [3]: np.datetime64('1970-01-01 00') - np.datetime64('1969-12-31 00')
Out[3]: 1 day, 0:00:00
In [4]:
On Tue, Apr 16, 2013 at 6:45 PM, Benjamin Root ben.r...@ou.edu wrote:
On Tue, Apr 16, 2013 at 7:45 PM, Ondřej Čertík ondrej.cer...@gmail.comwrote:
On Tue, Apr 16, 2013 at 4:55 PM, Bob Nnamtrop bob.nnamt...@gmail.com
wrote:
I am curious if others have noticed an issue with datetime64 at the
