On Thu, Jan 10, 2013 at 9:40 AM, Chao YUE chaoyue...@gmail.com wrote:
Dear all,
Are we going to consider returning the index of maximum value in an array
easily
without calling np.argmax and np.unravel_index consecutively?
This does seem like a good thing to support somehow. What would a
On Sat, 2013-01-12 at 00:26 +0100, Chao YUE wrote:
Hi,
I don't know how others think about this. Like you point out, one can
use
np.nonzero(a==np.max(a)) as a workaround.
For the second point, in case I have an array:
a = np.arange(24.).reshape(2,3,4)
suppose I want to find the
Dear all,
Are we going to consider returning the index of maximum value in an array
easily
without calling np.argmax and np.unravel_index consecutively?
I saw few posts in mailing archive and stackover flow on this, when I tried
to return
the index of maximum value of 2d array.
It seems that I
Hi Chao,
in two dimensions the following works very well:
In [97]: a = np.random.randn(5,7)
In [98]: a[divmod(a.argmax(), a.shape[1])]
Out[98]: 1.3680204597100922
In [99]: a.max()
Out[99]: 1.3680204597100922
In [100]:
In [100]: b = a[divmod(a.argmax(), a.shape[1])]
In [101]: b==a.max()
