I think this should be simple, but I'm drawing a blank
I have 2 2d matrixes
Matrix A has indexes (i, symbol)
Matrix B has indexes (state, symbol)
I combined them into a 3d matrix:
C = A[:,newaxis,:] + B[newaxis,:,:]
where C has indexes (i, state, symbol)
That works fine.
Now suppose I want
On Thursday, August 30, 2012, Neal Becker wrote:
I think this should be simple, but I'm drawing a blank
I have 2 2d matrixes
Matrix A has indexes (i, symbol)
Matrix B has indexes (state, symbol)
I combined them into a 3d matrix:
C = A[:,newaxis,:] + B[newaxis,:,:]
where C has indexes
On Thu, Aug 30, 2012 at 12:49 PM, Neal Becker ndbeck...@gmail.com wrote:
I think this should be simple, but I'm drawing a blank
I have 2 2d matrixes
Matrix A has indexes (i, symbol)
Matrix B has indexes (state, symbol)
I combined them into a 3d matrix:
C = A[:,newaxis,:] + B[newaxis,:,:]
Hi list,
Suppose I have array a with dimensions (d1, d3) and array b with
dimensions (d2, d3). I want to compute array c with dimensions (d1,
d2) holding the squared euclidian norms of vectors in a and b with
size d3.
My first take was to use a python level loop:
from numpy import *
c =
Hi Olivier
2008/12/4 Olivier Grisel [EMAIL PROTECTED]:
To avoid the python level loop I then tried to use broadcasting as follows:
c = sum((a[:,newaxis,:] - b) ** 2, axis=2)
But this build a useless and huge (d1, d2, d3) temporary array that
does not fit in memory for large values of d1, d2
2008/12/4 Stéfan van der Walt [EMAIL PROTECTED]:
Hi Olivier
2008/12/4 Olivier Grisel [EMAIL PROTECTED]:
To avoid the python level loop I then tried to use broadcasting as follows:
c = sum((a[:,newaxis,:] - b) ** 2, axis=2)
But this build a useless and huge (d1, d2, d3) temporary array that
On Thu, Dec 4, 2008 at 8:26 AM, Olivier Grisel [EMAIL PROTECTED]wrote:
Hi list,
Suppose I have array a with dimensions (d1, d3) and array b with
dimensions (d2, d3). I want to compute array c with dimensions (d1,
d2) holding the squared euclidian norms of vectors in a and b with
size d3.
2008/12/4 Charles R Harris [EMAIL PROTECTED]:
On Thu, Dec 4, 2008 at 8:26 AM, Olivier Grisel [EMAIL PROTECTED]
wrote:
Hi list,
Suppose I have array a with dimensions (d1, d3) and array b with
dimensions (d2, d3). I want to compute array c with dimensions (d1,
d2) holding the squared
2008/5/2 Chris.Barker [EMAIL PROTECTED]:
Hi all,
I have a n X m X 3 array, and I a n X M array. I want to assign the
values in the n X m to all three of the slices in the bigger array:
A1 = np.zeros((5,4,3))
A2 = np.ones((5,4))
A1[:,:,0] = A2
A1[:,:,1] = A2
A1[:,:,2] = A2
Charles R Harris wrote:
A1 += A2[:,:,newaxis] is one way.
Exactly what I was looking for -- thanks Charles (and Ann)
-Chris
--
Christopher Barker, Ph.D.
Oceanographer
Emergency Response Division
NOAA/NOS/ORR(206) 526-6959 voice
7600 Sand Point Way NE (206) 526-6329 fax
Hi all,
I have a n X m X 3 array, and I a n X M array. I want to assign the
values in the n X m to all three of the slices in the bigger array:
A1 = np.zeros((5,4,3))
A2 = np.ones((5,4))
A1[:,:,0] = A2
A1[:,:,1] = A2
A1[:,:,2] = A2
However,it seems I should be able to broadcast that, so I
On Thu, May 1, 2008 at 10:58 PM, Chris.Barker [EMAIL PROTECTED] wrote:
Hi all,
I have a n X m X 3 array, and I a n X M array. I want to assign the
values in the n X m to all three of the slices in the bigger array:
A1 = np.zeros((5,4,3))
A2 = np.ones((5,4))
A1[:,:,0] = A2
A1[:,:,1] = A2
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