Hello,
I have an array of datetime objects.
What is the most efficient way of creating a new array
with only the hours or minutes out of it?
Here is an example:
### imports
import numpy as np
import datetime as dt
### create some data
d = dt.datetime.now()
dates_li = []
count = 0
for i in
On Jan 28, 2009, at 3:56 PM, Timmie wrote:
### this is the loop I would like to optimize:
### looping over arrays is considered inefficient.
### what could be a better way?
hours_array = dates_array.copy()
for i in range(0, dates_array.size):
hours_array[i] = dates_array[i].hour
You
On Jan 28, 2009, at 5:43 PM, Timmie wrote:
You could try:
np.fromiter((_.hour for _ in dates_li), dtype=np.int)
or
np.array([_.hour for _ in dates_li], dtype=np.int)
I used dates_li only for the preparation of example data.
So let's suppose I have the array dates_array returned from a
a
