I have an recarray -- the first column is date.
I have the following function to compute the number of unique dates in
my data set:
def byName(): return(len(list(set(d['Date'])) ))
Question: is the string 'Date' looked up at each iteration? If so,
this is dumb, but explains my horrible
On Wed, Jul 21, 2010 at 15:12, wheres pythonmonks
wherespythonmo...@gmail.com wrote:
I have an recarray -- the first column is date.
I have the following function to compute the number of unique dates in
my data set:
def byName(): return(len(list(set(d['Date'])) ))
Question: is the
Wed, 21 Jul 2010 15:12:14 -0400, wheres pythonmonks wrote:
I have an recarray -- the first column is date.
I have the following function to compute the number of unique dates in
my data set:
def byName(): return(len(list(set(d['Date'])) ))
What this code does is:
1. d['Date']
Thank you very much better crack open a numpy reference manual
instead of relying on my python intuition.
On Wed, Jul 21, 2010 at 3:44 PM, Pauli Virtanen p...@iki.fi wrote:
Wed, 21 Jul 2010 15:12:14 -0400, wheres pythonmonks wrote:
I have an recarray -- the first column is date.
I have
However: is there an automatic way to convert a named index to a position?
What about looping over tuples of my recarray:
for t in d:
date = t['Date']
I guess that the above does have to lookup 'Date' each time.
But the following does not need the hash lookup for each tuple:
for t
On Jul 21, 2010, at 4:22 PM, wheres pythonmonks wrote:
However: is there an automatic way to convert a named index to a position?
What about looping over tuples of my recarray:
for t in d:
date = t['Date']
Why don't you use zip ?
for (date, t) in (d['Date'], d)
That way,
What about:
idx_by_name = dict(enumerate(d.dtype.names))
Then I can look up the index of the columns I want before the loop,
and then access by the index during the loop.
- W
On Wed, Jul 21, 2010 at 4:29 PM, Pierre GM pgmdevl...@gmail.com wrote:
On Jul 21, 2010, at 4:22 PM, wheres
On Jul 21, 2010, at 4:35 PM, wheres pythonmonks wrote:
What about:
idx_by_name = dict(enumerate(d.dtype.names))
Then I can look up the index of the columns I want before the loop,
and then access by the index during the loop.
Sure. Why don't you try both approaches, time them and
My code had a bug:
idx_by_name = dict((n,i) for i,n in enumerate(d.dtype.names))
On Wed, Jul 21, 2010 at 4:49 PM, Pauli Virtanen p...@iki.fi wrote:
Wed, 21 Jul 2010 16:22:37 -0400, wheres pythonmonks wrote:
However: is there an automatic way to convert a named index to a
position?
It's
