Analogamente, n^4 + n^2 +1 = n^4+2n²+1 - n² = (n²+1)²-n² = (n²+n+1)(n²-n+1)
2009/4/24 benedito bened...@ufrnet.br
Josimar,
Veja que n^4 + 4 = n^4 + 4n^2 - 4n^2 + 4 = (n^4 + 4n^2 + 4) - 4n^2 = (n^2
+2)^2 - (2n^2)^2 =
= (n^2 +2 + 2n^2)(n^2 +2 - 2n^2)
Benedito
n^4 + n^2 + 1 = n^4 + 2n^2 + 1 -n^2 = (n^2 +1)^2 - n^2 = (n^2 +1 +n)(n^2+1
-n)
2009/4/24 benedito bened...@ufrnet.br
Josimar,
Veja que n^4 + 4 = n^4 + 4n^2 - 4n^2 + 4 = (n^4 + 4n^2 + 4) - 4n^2 = (n^2
+2)^2 - (2n^2)^2 =
= (n^2 +2 + 2n^2)(n^2 +2 - 2n^2)
Benedito
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