Hi Georg,
I’d say yes but do it reluctantly :) you can think in terms of iteration
but in my experience it leads to incorrect assumptions and can confuse you,
especially regarding how result sets are created
I’d suggest thinking in terms of pattern matching rather than traversal but
both are valid
Hi Seref,
Ok, thank you for the answer.
From that I and the other answers I would summarize that
"implicit iteration over lists in order to further process the elements"
is a paradigm that does actually exist in AQL.
Greetings
Georg
--
Have you seen a previous answer I gave to you re contains clause and nodes
without arch nd ids? The one explaining why it is unlikely to work
a/items[at0001]/value/value should do the trick
On Sunday, May 5, 2019, Georg Fette wrote:
> Hello,
> In order to better understand the semantics of AQL
Hello,
In order to better understand the semantics of AQL I try to rephrase the
problem I have:
Imagine an archetype "openEHR-EHR-CLUSTER.example.v1" that allows the
multiple existence of a specific contained field:
definition
CLUSTER[at] matches {
items cardinality matches
Hi Thomas,
I do not want to use the path element "items[at0001]" multiple times.
What I mean is that in the query
SELECT a/items[at0001]/value
FROM EHR e CONTAINS CLUSTER
a[openEHR-EHR-CLUSTER.laboratory_test_analyte.v1]
the path "a/items[at0001]" denotes a list of ELEMENT (min: 0, max: *).
Yes that at codes are always effectively namespaced by their parent
archetype.
Ian
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Unless I am missing something, the fragment items[at0001] cannot appear
more than once /relative to any given archetype/. Here, it is relative
to 'a', i.e. openEHR-EHR-CLUSTER.laboratory_test_analyte.v1. Within the
same archetype, you cannot have other items[xxx] such that the xxx are
not
Hello,
Is it allowed to use an element that is allowed to appear multiple times
within a path ?
For example in the query
SELECT a/items[at0001]/value
FROM EHR e
CONTAINS CLUSTER a[openEHR-EHR-CLUSTER.laboratory_test_analyte.v1]
the field items[at0001] may appear 0..* times. Thus
8 matches
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