Hi Sugumar,
I might misunderstand your need but 'Hex' (as 'Base64') is just an encoding
method to ease use of characters that are not printable.
Your example hex string IV : "12345678901234567890123456789012" should be
converted to :
unsigned char IV[16] = { 0x12, 0x34, 0x56, 0x78, 0x90, 0x12,
Thanks for your reply.
Correct me if i am wrong.
What i have understood from your point is, i have to read the first 2 char
of 32 char IV and convert into a byte array right?
For example: my IV "12345678901234567890123456789012"
I have read first 2 char i.e "12" then i have to convert it into
> Then i am passing this cipher text to my another end which is using a
> python(PyCrypto library) code to decrypt a cipher text using same Key and
> IV.
The IV, key, and ciphertext are all binary arrays of bytes. Not C (or ASCII or
UTF8 or anything) strings. You will have to convert back/and
Hi,
I have encrypted a free text in C++ using a EVP calls with CFB mode and 32
bytes of IV (Hex String).
Then i am passing this cipher text to my another end which is using a
python(PyCrypto library) code to decrypt a cipher text using same Key and
IV.
But i am getting error "IV must be of 16
