Hi,
On 13/12/2022 23:54, Arne Schwabe wrote:
We have 6 key slots but normally only consider 3 of them to be
active/valid keys. Especially the secondary key of TM_LAME_DUCK can
in rare corner cases have a key that is still installed in the kernel.
While this should not cause any issues since I do not see way for this
key to become active ever again, it is better to keep the state correctly.
Signed-off-by: Arne Schwabe
I am fine with this because it is just "safer".
But I truly dislike that we have to "Defend ourselves" from conditions
which we don't even know when they may happen
Still, this is a rant for another patch/cleanup.
This patch makes sense
Acked-by: Antonio Quartulli
---
src/openvpn/dco.c | 14 +-
1 file changed, 9 insertions(+), 5 deletions(-)
diff --git a/src/openvpn/dco.c b/src/openvpn/dco.c
index 36bfbf10a..20196fe5d 100644
--- a/src/openvpn/dco.c
+++ b/src/openvpn/dco.c
@@ -221,13 +221,17 @@ dco_update_keys(dco_context_t *dco, struct tls_multi
*multi)
multi->dco_keys_installed = 1;
}
-/* all keys that are not installed are set to NOT installed */
-for (int i = 0; i < KEY_SCAN_SIZE; ++i)
+/* all keys that are not installed are set to NOT installed. Include also
+ * keys that might even be considered as active keys to be sure*/
+for (int i = 0; i < TM_SIZE; ++i)
{
-struct key_state *ks = get_key_scan(multi, i);
-if (ks != primary && ks != secondary)
+for (int j = 0; j < KS_SIZE; j++)
{
-ks->dco_status = DCO_NOT_INSTALLED;
+struct key_state *ks = >session[i].key[j];
+if (ks != primary && ks != secondary)
+{
+ks->dco_status = DCO_NOT_INSTALLED;
+}
}
}
return true;
--
Antonio Quartulli
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