Awesome! FWIW, the desired result is achieved without the GROUP BY at the
end. So the following does the same thing:
SELECT
DriverID, DriverName, list(CarCost)
FROM ( MATCH {...} RETURN ...)
I have to admit that I still don't fully understand what list() is doing.
The documentation doesn't
SELECT
DriverID, DriverName, list(CarCost)
FROM ( ... )
GROUP BY DriverID, DriverName
Il giorno gio 7 mar 2019 alle ore 12:27 Luigi Dell'Aquila <
luigi.dellaqu...@gmail.com> ha scritto:
> oh, sorry, I didn't scroll the screen :D
>
> You have to use a set() or list() aggregation on CarCost and
