[PD] [bp~] really equal to [vcf~]?

Hi there, who can confirm that both [bp~] and [vcf~] are exactly the really same thingy? The code looks quite different... Moreover, why the two outlets for vcf~? Help doesn't say anything. Thanks ___ Pd-list@iem.at mailing list UNSUBSCRIBE and

Re: [PD] [bp~] really equal to [vcf~]?

They're quite different. bp~ is the cheapest possible bandpass filter (as far as I know). vcf~ is a one-pole complex filter whose outputs are the real and imaginry parts. The real part may be used as a resonant bandpass filter and the imaginary as a resonant low-pass filter, but they can be

Re: [PD] [bp~] really equal to [vcf~]?

that's great to know, thanks! Let me just see if I get a bit of the theory. Can I get [vcf~] with just one [cpole~] object and the right coeficients? Cheers 2014-04-12 13:36 GMT-03:00 Miller Puckette m...@ucsd.edu: They're quite different. bp~ is the cheapest possible bandpass filter (as

Re: [PD] [bp~] really equal to [vcf~]?

Yep - vcf~ is essentially a wrapper for cpole~. cheers M On Sat, Apr 12, 2014 at 02:10:19PM -0300, Alexandre Torres Porres wrote: that's great to know, thanks! Let me just see if I get a bit of the theory. Can I get [vcf~] with just one [cpole~] object and the right coeficients? Cheers