On Fri, Feb 24, 2012 at 12:46:13PM -0500, Mathieu Bouchard wrote:
Le 2012-02-24 à 09:07:00, Frank Barknecht a écrit :
I made it half signal-rate: The object accepts signal parameters, but
these are just linearly interpolated internally, i.e. they don't move
correctly on a circle.
If you
On Sun, Feb 19, 2012 at 11:33:28AM -0500, Mathieu Bouchard wrote:
Le 2012-02-03 à 09:46:00, Frank Barknecht a écrit :
Most filters in the rj library (https://github.com/rjdj/rjlib) use a
similar approach. They even include a biquad-clone written with
elementary filters.
Why would you
Le 2012-02-24 à 09:07:00, Frank Barknecht a écrit :
I made it half signal-rate: The object accepts signal parameters, but
these are just linearly interpolated internally, i.e. they don't move
correctly on a circle.
If you interpolate, it means that you are doing something at non-signal
Le 2012-02-03 à 09:46:00, Frank Barknecht a écrit :
Most filters in the rj library (https://github.com/rjdj/rjlib) use a
similar approach. They even include a biquad-clone written with
elementary filters.
Why would you clone biquad using elementary filters ? Is it just to show
that it's
Le 2012-02-02 à 19:13:00, Mike Moser-Booth a écrit :
a = -r²
b = 2r*cos(ω)
c = 1 (an overall gain is applied separately, which is like scaling a,b,c
all at once)
I don't think this is entirely accurate. I think a and c should be
switched here, though of course when finding b²-4ac that doesn't
On Sun, Feb 19, 2012 at 1:04 PM, Mathieu Bouchard ma...@artengine.ca wrote:
Le 2012-02-02 à 19:13:00, Mike Moser-Booth a écrit :
I don't think this is entirely accurate. I think a and c should be
switched here, though of course when finding b²-4ac that doesn't
really matter.
It depends
Le 2012-02-19 à 14:08:00, Mike Moser-Booth a écrit :
Pretty sure, though I mess that up all the time. Aren't you supposed
change the signs of the feedback coefficients when z-transforming the
difference equation?
Why would you change the signs of a and b but not c ?
(Was I giving the
On Sun, Feb 19, 2012 at 4:54 PM, Mathieu Bouchard ma...@artengine.ca wrote:
Why would you change the signs of a and b but not c ?
(Was I giving the formula relative to ax²+bx+c=0 or did I assume ax²+bx=c by
accident ?)
I think it has to do with where c is in the difference equation:
c*y[n] =
Le 2012-02-19 à 17:48:00, Mike Moser-Booth a écrit :
On Sun, Feb 19, 2012 at 4:54 PM, Mathieu Bouchard ma...@artengine.ca wrote:
Why would you change the signs of a and b but not c ?
(Was I giving the formula relative to ax²+bx+c=0 or did I assume ax²+bx=c by
accident ?)
I think it has to do
On Sun, Feb 19, 2012 at 6:12 PM, Mathieu Bouchard ma...@artengine.ca wrote:
Le 2012-02-19 à 17:48:00, Mike Moser-Booth a écrit :
On Sun, Feb 19, 2012 at 4:54 PM, Mathieu Bouchard ma...@artengine.ca
wrote:
Why would you change the signs of a and b but not c ?
(Was I giving the formula
Le 2012-02-19 à 22:31:00, Mike Moser-Booth a écrit :
To clarify, think of the z-transform of the filter as H(z) = 1/A(z),
where A(z) = 1 - 2r*cos(ω)*z^-1 + r^2*z^-2. If we decide c=1,
b=2r*cos(ω), and a=r^2, we have A(z) = c - bz^-1 + az^-2. In order to
apply the quadratic formula, those
On Sun, Feb 19, 2012 at 10:41 PM, Mathieu Bouchard ma...@artengine.ca wrote:
Curiously (but not interestingly), it's in d_osc.c instead of d_filter.c.
This makes no sense and you shouldn't try to make sense of it. Just use grep
or any other means to search multiple files for a word, and you'll
On Thu, Feb 02, 2012 at 03:32:00AM +, Ed Kelly wrote:
Here is my first attempt at making a resonant lowpass filter using cpole~ and
czero~ objects. It's the first version I've made which actually sounds
halfway towards what I want to achieve, which is a decent diode-ladder or
De: Ed Kelly morph_2...@yahoo.co.uk
Hi all,
Here is my first attempt at making a resonant lowpass filter using
cpole~ and czero~ objects. It's the first version I've made which
actually sounds halfway towards what I want to achieve, which is a
decent diode-ladder or transistor-ladder
On 2/2/12, Patrice Colet colet.patr...@free.fr wrote:
De: Ed Kelly morph_2...@yahoo.co.uk
Hi all,
Here is my first attempt at making a resonant lowpass filter using
cpole~ and czero~ objects. It's the first version I've made which
actually sounds halfway towards what I want to achieve,
Le 2012-02-02 à 12:50:00, Patrice Colet a écrit :
De: Ed Kelly morph_2...@yahoo.co.uk
Here is my first attempt at making a resonant lowpass filter using
cpole~ and czero~ objects.
using biquad~ gives very nice results for resonant filtering, ggee audio
filters show how it sounds. It should be
Le 2012-02-02 à 11:40:00, Mathieu Bouchard a écrit :
So a real ax²+bx+c is something between a pair of [rpole~] and a pair of
[cpole~]. It's equivalent to a pair of [cpole~] in which you force two
numbers to be the same, and two other numbers to be negatives of each other.
Actually, [bp~] is
On Thu, Feb 2, 2012 at 1:37 PM, Mathieu Bouchard ma...@artengine.ca wrote:
Le 2012-02-02 à 11:40:00, Mathieu Bouchard a écrit :
Actually, [bp~] is pretty much a 2-pole resonant real filter, right ?
Yep. Both poles sit right on top of each other along the real axis.
The input parameters f
Hi all,
Here is my first attempt at making a resonant lowpass filter using cpole~ and
czero~ objects. It's the first version I've made which actually sounds halfway
towards what I want to achieve, which is a decent diode-ladder or
transistor-ladder filter emulation. I want to make this using
Ooops! Here's the patch.
Gemnotes-0.1alpha: Live music notation for Pure Data
http://sharktracks.co.uk/
filter_0.01.pd
Description: Binary data
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