OK, that's clear, thanks. Still when using [tabread4~] or [tabosc4~] you
still need a copy of the last element in the first index and copies of the
first two elements in the last two indices, right? Even if you're not using
sinesum or cosinesum but some other mathematical function..
On Thu, Sep 5
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On 2013-09-05 09:45, Alexandros Drymonitis wrote:
> OK, index 0 is the negative of index 2,
no not really, they just happen to be the same.
> which can again make sense as it's a sine (supposing that index 0
> is a copy of the table's last element),
When you send this message [sinesum 512 1( to a table Pd will automatically
add one index to the beginning of the table and two indices to its end, and
you end up with a table of 515 indices. The three additional indices are
the guard points for the cubic interpolation, right? So the first index
sh
