On Mon, 2014-03-17 at 18:59 -0400, Jonathan Wilkes wrote:
On 03/17/2014 04:34 PM, Roman Haefeli wrote:
On Mon, 2014-03-17 at 02:21 -0300, Alexandre Torres Porres wrote:
Hi Roman. This is turning out trickier than I thought.
I think I understand now what you are trying to achieve (sorry,
No, the code I ported is from vslider_set and vslider_draw_update (might be
different in Vanilla).
In vslider_bang, math is done to output the proper value. Without looking at
the code I would have guessed vslider_bang simply outputs a stored value like
[float] does. Then just do math to set
the solution is as I thought, to just invert the given formula in the code.
Someone helped me with the math, is something like
expr ln($f1 / 1.27) / (((log(127 / 1.27) / 1.27)) * 0.01)
here's a patch attached
I'm finally gonna check what kind of curve this thing gives :)
Thanks everyone
but when we use the slider with the log function, we're actually doing an
inversion of this graphs I just posted. In other words, what we do is the
first formula that is actually from the code. So using that formula was
actually right to begin with.
Check my patch attached now
2014-03-18 17:05
just be sure to click the message, should have put a loadbang there, sorry
2014-03-18 17:16 GMT-03:00 Alexandre Torres Porres por...@gmail.com:
but when we use the slider with the log function, we're actually doing an
inversion of this graphs I just posted. In other words, what we do is the
cool, looks great
by the way, this guy was helping me out with the math, so I don't really
know what's going on that well.
Apparently he couldn't figure out the slider height variable. And Roman
didn't use that too.
The formula was behaving the same as Roman's patch, but we simplified the
Hey, a few things have made sense to me now.
The minimum and maximum values in PD are in a 100 / 1 ratio. This ratio is
important and it's a key in the formula. In the sense that if you have 10
and 1000, the plotting curve looks always the same. So if you forget about
the minimum and maximum
here's what I got as an abstraction
2014-03-18 21:12 GMT-03:00 Alexandre Torres Porres por...@gmail.com:
Hey, a few things have made sense to me now.
The minimum and maximum values in PD are in a 100 / 1 ratio. This ratio is
important and it's a key in the formula. In the sense that if you
there's a bug in one of the number boxes, sorry
2014-03-18 23:37 GMT-03:00 Alexandre Torres Porres por...@gmail.com:
here's what I got as an abstraction
2014-03-18 21:12 GMT-03:00 Alexandre Torres Porres por...@gmail.com:
Hey, a few things have made sense to me now.
The minimum and
AFAICT vslider is saving something like a slider position, and your expression
above (along with the code I posted) is for getting back the original value
from it. If you send it something between 0.01 and 1 you'll get a curve that's
inverted from the one you're after. If you send it a slider
so you say this is actually the section of the code I'm looking for to make
the conversion I want, right?
==
static void hslider_set(t_hslider *x, t_floatarg f)/* bugfix */
{
double g;
if(x-x_gui.x_isa.x_reverse)/* bugfix */
{
if(f x-x_min)
f =
On Mon, 2014-03-17 at 02:21 -0300, Alexandre Torres Porres wrote:
Hi Roman. This is turning out trickier than I thought.
I think I understand now what you are trying to achieve (sorry, took me
a long time). But I don't really have a clue how to do it. The
abstraction I posted emulates the output
On 03/17/2014 04:34 PM, Roman Haefeli wrote:
On Mon, 2014-03-17 at 02:21 -0300, Alexandre Torres Porres wrote:
Hi Roman. This is turning out trickier than I thought.
I think I understand now what you are trying to achieve (sorry, took me
a long time). But I don't really have a clue how to do
Hi Roman. This is turning out trickier than I thought. A friend explained
the code to me and got to the following equation, with min/max values as
0.01 and 1 respectively.
[expr 0.01 * exp((log(1 / 0.01) / 0.01) * $f1 * 0.01)]
For what I've checked, it seems to behave like your patch. But it
On Don, 2014-03-06 at 21:37 -0300, Alexandre Torres Porres wrote:
hi folks, out of curiosity, what's the exact log function used in the
slider? I'd like to emulate it.
I am not sure, if this is what you want. It converts the incoming linear
range between 0 and 1 to a logarithmic range specified
Thanks Jonathan. Unfortunately, my C expertise is kinda poor and I'm still
lost. I see it's got something to do with [exp] but haven't got my head
around the function needed to emulate it. I'm making extensive
documentation about Pd, so I'd like to write about it. I find it worth
noting.
In the
Wow, never mind-- it's a veritable Rube Goldberg machine of code to get from an
incoming float to an outgoing one in g_vslider.c. There's even more math to
draw the tick and I can't figure out how it works at the moment.
I also love how tempting log is for a volume control, but then it
hi folks, out of curiosity, what's the exact log function used in the
slider? I'd like to emulate it.
cheers
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From g_vslider.c:
if(x-x_lin0_log1)
out = x-x_min*exp(x-x_k*(double)(x-x_val)*0.01);
Where x-x_k is:
log(x-x_max/x-x_min)/(double)(x-x_gui.x_h - 1);
And x-x_gui.x_h is the height of the slider
-Jonathan
On Thursday, March 6, 2014 7:37 PM, Alexandre Torres Porres
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